#1
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Odds of at least one player holding 72 on an 8-man table.
While watching the new HSP episode I was wondering how often you will see hands with one player (or more) holding 72. It is 8-handed, right?
So I made some amateurish calculations and came up with 16.18%. Maybe a probability buff can confirm this? Thanks in advance. |
#2
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Re: Odds of at least one player holding 72 on an 8-man table.
The probability no individual player holds 7-2 is (1326-16)/1326 . Now take this number to the 8th power and take the complement . This is a good enough approximation .
9.255% . |
#3
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Re: Odds of at least one player holding 72 on an 8-man table.
[ QUOTE ]
While watching the new HSP episode I was wondering how often you will see hands with one player (or more) holding 72. It is 8-handed, right? So I made some amateurish calculations and came up with 16.18%. Maybe a probability buff can confirm this? Thanks in advance. [/ QUOTE ] The exact answer, by the inclusion-exclusion principle for 72o or 72s is: 8*16/C(52,2) - C(8,2)*16*9/C(52,2)/C(50,2) + C(8,3)*16*9*4/C(52,2)/C(50,2)/C(48,2) - C(8,4)*16*9*4*1/C(52,2)/C(50,2)/C(48,2)/C(46,2) =~ 9.407% or 9.6-to-1 A good and easy approximation is: 1 - (1310/1326)^8 =~ 9.255% or 9.8-to-1 |
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