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#1
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...but their combined attractiveness can only total 10, how many ladies do you go for and how do you distribute their attractiveness? Let's say that you have to have a minimum of two girls, that other aspects of their being are stereotypical for their looks (intelligence, sense of humor, etc), and that each wife/girlfriend are knowingly involved in this polygamous relationship and that there are no conflicts between them.
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#2
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who cares
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#3
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Can I have a avg 6 and a 4 that's a real fatty with a cute face?
I think I need to be able to go over 10 before this is a better offer than just one hot chick. |
#4
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1.
carlin- "i never f'd a 10, but one night i f'd 5 2s and i think that should count" |
#5
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Ehh...I might pass. Two 5's is beat, you'd have to be seen in public with at least one of them sometime. A 7 is OK for public, but [censored] a 3 is - EV no matter how many sets of lips are on your balls.
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#6
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[ QUOTE ]
a 4 that's a real fatty with a cute face? [/ QUOTE ] She'd have to be pretty damn fat to only be a 4, esp w/ a cute face. |
#7
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this is a v good q.
Here's the rub, what if you like fat chicks like moi? Many chicks I'd rate an 8 many would rate a 3. I.e. I win this game I think. 5 2s not close final answer. |
#8
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Are we just plain adding or using the Pythagorean Theorem here?
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#9
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[ QUOTE ]
this is a v good q. Here's the rub, what if you like fat chicks like moi? Many chicks I'd rate an 8 many would rate a 3. I.e. I win this game I think. 5 2s not close final answer. [/ QUOTE ] I think to be fair you have to use your own rankings, and not generalized ones, otherwise all sorts of freaks could be happy with 5 "2"s like yourself. |
#10
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what if they're ugly but their [censored] and bungholes are super tight?
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