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  #1  
Old 05-08-2007, 01:32 AM
PokerFox PokerFox is offline
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Default won a seat to the FTP 100 seats ME sat - how many entrants last year?

So they say 100 seats, but I know there will be a ton registered direct + more sats. How many did they have last year and any accurate predictions on this year?

Thanks,
pf
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  #2  
Old 05-08-2007, 02:15 AM
LLKOOLK1 LLKOOLK1 is offline
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Default Re: won a seat to the FTP 100 seats ME sat - how many entrants last ye

Appx 150 if i remeber correctly
-L
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  #3  
Old 05-08-2007, 02:19 AM
PokerFox PokerFox is offline
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Default Re: won a seat to the FTP 100 seats ME sat - how many entrants last ye

150 seats, but like 5000, 7000, 10000 entrants? That's what I was curious about.
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  #4  
Old 05-08-2007, 02:24 AM
THAY3R THAY3R is offline
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Default Re: won a seat to the FTP 100 seats ME sat - how many entrants last ye

Probably something like 150 * (Prize / Buyin)
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  #5  
Old 05-08-2007, 02:25 AM
PokerFox PokerFox is offline
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Default Re: won a seat to the FTP 100 seats ME sat - how many entrants last ye

wow. oops.

I play poker real good. Can't even multiply, or come to that solution myself.

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Edit: although it's more like 150 * package worth (12,000) then divided by buyin. But thanks for putting me on the right track [img]/images/graemlins/smile.gif[/img]
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  #6  
Old 05-08-2007, 09:08 AM
Confused1 Confused1 is offline
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Default Re: won a seat to the FTP 100 seats ME sat - how many entrants last ye


[ QUOTE ]
wow. oops.

I play poker real good. Can't even multiply , or come to that solution myself.

Lock thread!


[/ QUOTE ]
[ QUOTE ]
although it's more like 150 * package worth (12,000) then divided by buyin

[/ QUOTE ]

LOL, you're right - you shouldn't be argueing math.

What you said and what Thay3r said is the same thing, mathematically.

Just like (4 * 3) * 9 = 4 * (3 * 9) ;

(150 * Prize) * (1/buyin) = 150 * (Prize * 1/buyin)
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  #7  
Old 05-08-2007, 10:22 AM
 is offline
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Default Re: won a seat to the FTP 100 seats ME sat - how many entrants last ye

PEMDAS.

Thread over.
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