knowing outs

[rontime]

When counting outs, with 47 unseen cards, say I have 6 outs so 47/6 which is 6to1 or 7to1? Then with 46 unseen still with 6 outs is it 46/6 which gives me 7.6, so it would be 6to1? They just dont seem to add up correctly I'm not doing the math right somewere because it looks like I got the same amont of outs with 47 or 46 cards left.
I thank you for any help

[mp3]

If you have 6 outs and 5000 unseen cards.. you still have 6 outs.

[AdoptedDog]

With 47 unseen cards and 6 outs, you are roughly 1 in 8 to make your hand, or roughly 7-to-1 against. The number of outs doesn't change just your odds.

[SheridanCat]

[ QUOTE ]
When counting outs, with 47 unseen cards, say I have 6 outs so 47/6 which is 6to1 or 7to1? Then with 46 unseen still with 6 outs is it 46/6 which gives me 7.6, so it would be 6to1? They just dont seem to add up correctly I'm not doing the math right somewere because it looks like I got the same amont of outs with 47 or 46 cards left.
I thank you for any help

[/ QUOTE ]

The odds against you making your hand on the next card will change very little:

After the flop: 47 unseen cards, 6 of which will help you and 41 will not help you. The odds against you making your hand are 41:6. Since you want the odds on the right to be 1, if possible, divide both sides by 6 to get 6.83:1 against you making your hand.

After the turn: 46 unseen cards, 6 of which help and 40 that don't. So, 40:6 or 6.66:1 against.

So, yes, it's roughly the same odds against, twice.

[Grunch]

There are 2 ways to express the chance that you will draw a card you need: probability and odds. They aren't the same. Probability is expressed as a percentage, odds is expressed as "x to y".

If you have 6 outs and there are 47 unseen cards, the probability that you'll draw one of your outs on the next card is 6/47 = ~13%.

Odds are expressed as "x to y" where x is the number of times you hit and y is the number of times you miss. So the odds that you'll hit one of your outs on the next card are 6:41. 6 cards are good for you, and the rest (47-6=41) are not. You can reduce this to 1:something simply by dividing both sides by 6; so this is 1:6.8

If you want to compute the probability of your draw at the table, you don't have to do division. You can use the rule of 2 & 4. Take the number of outs you have and multiply it by 2. In this case, that's 12. And that's the probability of your draw with one card to come; 12%. This is close enough, dont worry about the error. Now take the number of outs and multiply it by 4. In this case, that's 24. Ther is a 24% chance that your draw will come in with two more cards to come. Again there's some error, but this is close enough.

[A_F]

Well put Grunch. Better than most books explain it. A lot of players get this wrong.

[rontime]

SORRY FOR LATE REPLY,
thanks Grunch I'll try this and see how it works at the tables