#1
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Anyone know the odds of this?
Had a 6max hand last night where I was dealt two red aces, sure enough the player I was up against had two black aces and we split.
What are the odds of two people at 6max getting dealt aces in the same hand? |
#2
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Re: Anyone know the odds of this?
who cares
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#3
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Re: Anyone know the odds of this?
[ QUOTE ]
who cares [/ QUOTE ] [img]/images/graemlins/heart.gif[/img] |
#4
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Re: Anyone know the odds of this?
[ QUOTE ]
who cares [/ QUOTE ] Obviously, I care or I wouldn't have asked. Anyone have a legit reply? |
#5
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Re: Anyone know the odds of this?
It's INCONCEIVABLE
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#6
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Re: Anyone know the odds of this?
[ QUOTE ]
It's INCONCEIVABLE [/ QUOTE ] ZOMG, I kNOW!!!111!!!! I yelled "SO RiGGeD" and threw my mouse. |
#7
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Re: Anyone know the odds of this?
[ QUOTE ]
It's INCONCEIVABLE [/ QUOTE ] I don't think that word means what you think it means. |
#8
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Re: Anyone know the odds of this?
It usually happens once every 7 hands or so. Online sites just want our rake!!!
Seriously though, if my calculations are correct (thats a longshot [img]/images/graemlins/wink.gif[/img] ), it is once every 9,024 hands. |
#9
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Re: Anyone know the odds of this?
[ QUOTE ]
[ QUOTE ] It's INCONCEIVABLE [/ QUOTE ] You keep using that word...I do not think it means what you think it means. [/ QUOTE ] FYPBQP. <-----nit |
#10
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Re: Anyone know the odds of this?
10 handed, if you are dealt aces, prob of somone with AA if you already hold AA is 1/136.
this site shows the process of the calc, so you can adjust it to 6max if you want. Then multiply it by odds of getting dealt AA, then multiply new one by 1/221 so for 10 handed, it's: (1/221) * (1/136) |
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