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#1
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I've been recently reading about this, and I think this is ok.
"Pick a number. Roll a die 3 times. How often will that number come up in at least 1 roll?" This is what i got: 5/6 x 5/6 x 1/6 = 25/216 (x3) = 75/216 plus 5/6 x 1/6 x 1/6 = 5/216 (x3) = 15/216 plus 1/6 x 1/6 x 1/6 = 1/216 (x1) = 1/216 equals 91/216, or 42.1% Right? |
#2
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roll 3 dice, what are the odds that none of them are a 6?
(5/6)*(5/6)*(5/6) = 125/216 what are the odds that at least one of them is a 6? 1 - 125/216 = 91/216 you are right |
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