#1
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The Odds Must Be Insane!!!
Anybody know what the odds of holding hole cards and the board showing up all cards that match your hole cards?
E.X. Hole cards J10 The board JJJ1010 I just happened to me |
#2
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Re: The Odds Must Be Insane!!!
Odds of being dealt a non-pair = .94
Total possible boards = 50 choose 3 = 19,600 Number board appearing with a full house of your two non-paired cards = 6 6 / 19,600 = .00030612244897959183673469387755102 .94 * .000306 = 0.00028764 In other words once every 3,476 hands, approx. |
#3
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Re: The Odds Must Be Insane!!!
No cigar.
Total possible boards is 50 choose 5. |
#4
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Re: The Odds Must Be Insane!!!
Correct, I realized this later.
50 choose 5 = 2,118,760 6 / 2,118,760 = 2.83e-6 .94 * 2.8318450414393324397288980346995e-6 = 7.538e-12 Or rather once every 132,657,917,777 hands correct? |
#5
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Re: The Odds Must Be Insane!!!
Right.
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#6
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Re: The Odds Must Be Insane!!!
[ QUOTE ]
.94 * 2.8318450414393324397288980346995e-6 = 7.538e-12 [/ QUOTE ] OK, what am I missing? |
#7
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Re: The Odds Must Be Insane!!!
You took a number with an order of magnitude of 10^-6, multiplied it by .94 and wound up with a number of order of magnitude 10^-12.
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#8
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Re: The Odds Must Be Insane!!!
[ QUOTE ]
I just happened to me [/ QUOTE ] 100% |
#9
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Re: The Odds Must Be Insane!!!
Yet another reason to avoid RTG casinos.
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#10
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Re: The Odds Must Be Insane!!!
My only friends in those calculations were my brain and MS calculator, so cut me some slack, I'm sure I made some errors here and there, what are the correct numbers btw?
I see that multiplication should be 2.6619343389529724933451641526171e-6 (not e-12) |
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