Two Plus Two Newer Archives  

Go Back   Two Plus Two Newer Archives > General Gambling > Probability
FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
  #1  
Old 10-26-2007, 07:36 PM
SeanC SeanC is offline
Senior Member
 
Join Date: Sep 2007
Posts: 108
Default Understanding normal distribution graphs

Hey,

What do the x and y values on a normal distribution graph refer to? X=standard deviation and y=mean?

Thanks.
Reply With Quote
  #2  
Old 10-26-2007, 08:18 PM
SeanC SeanC is offline
Senior Member
 
Join Date: Sep 2007
Posts: 108
Default Re: Understanding normal distribution graphs

Okay, I found that the horizontal numbers refer to SD, but what about the vertical? Are they just arbitrary numbers assigned based on the height of the curve for use in calculations?
Reply With Quote
  #3  
Old 10-26-2007, 08:46 PM
DrVanNostrin DrVanNostrin is offline
Senior Member
 
Join Date: Sep 2005
Location: throwing my cards at the dealer
Posts: 656
Default Re: Understanding normal distribution graphs

I'm not sure exactly what you're talking about, but I'll take a stab. You were probably looking at a normal(0,1) distibution. This a normal distribution with a mean of 0 and SD of 1. If this is the case the x-values do correspond to z-scores. The y-values are a little more complicated.

Since a normal distribution is continous the probability of getting any exact value is 0 (there are an infinite amount of possible outcomes). However the area under the curve is equal to the probability of falling in that region. For example, the region bounded by x = -1, x = 1, y=0 and the distribution itself would have an area of 0.68. If you were to integrate from x = -1 to x = 1 the result would be 0.68 (you can't integrate a normal distribution using standard techniques). For any continous distribution the integral from -infinity to infinity must equal 1.
Reply With Quote
  #4  
Old 10-26-2007, 08:53 PM
SeanC SeanC is offline
Senior Member
 
Join Date: Sep 2007
Posts: 108
Default Re: Understanding normal distribution graphs

Hey Dr,

Thanks for the reply. I actually do understand that and this whole thing is starting to come into focus. The only thing left that I don't quite get is this idea of "normal (0,1) distribution." What if you're calculating for something that has a mean of, let's say, 100, and an SD of 50?

Thanks.
Reply With Quote
  #5  
Old 10-26-2007, 09:38 PM
DrVanNostrin DrVanNostrin is offline
Senior Member
 
Join Date: Sep 2005
Location: throwing my cards at the dealer
Posts: 656
Default Re: Understanding normal distribution graphs

That's what z-scores are for.
Reply With Quote
  #6  
Old 10-28-2007, 10:16 PM
Paul2432 Paul2432 is offline
Senior Member
 
Join Date: Jun 2003
Location: Bryn Mawr, PA USA
Posts: 1,458
Default Re: Understanding normal distribution graphs

[ QUOTE ]
Since a normal distribution is continous the probability of getting any exact value is 0 (there are an infinite amount of possible outcomes).

[/ QUOTE ]

If the probability of any particular outcome is zero, how does anything ever happen? (assuming something with a zero probability cannot happen)

Paul
Reply With Quote
  #7  
Old 10-29-2007, 12:35 AM
DrVanNostrin DrVanNostrin is offline
Senior Member
 
Join Date: Sep 2005
Location: throwing my cards at the dealer
Posts: 656
Default Re: Understanding normal distribution graphs

[ QUOTE ]
If the probability of any particular outcome is zero, how does anything ever happen? (assuming something with a zero probability cannot happen)

[/ QUOTE ]
I may not know enough about the subject to answer this correctly. But this is how I think about it. Let me know if I'm wrong.

Since a continious distribution is made up of an infinite number of mutually exclusive possibilies, the probably of one of those events occuring is infinity*0. Which is not equal to zero.

let C be some real finite number greater than 0

C/infinity = 0

infinity*0 = C > 0
Reply With Quote
  #8  
Old 10-30-2007, 11:42 PM
Grizwold Grizwold is offline
Senior Member
 
Join Date: Sep 2005
Location: Non-Self-Weighting Class
Posts: 228
Default Re: Understanding normal distribution graphs

Hi Paul,

[ QUOTE ]
[ QUOTE ]
If the probability of any particular outcome is zero, how does anything ever happen? (assuming something with a zero probability cannot happen)

[/ QUOTE ]

...a continuous distribution is made up of an infinite number of mutually exclusive possibilities…

[/ QUOTE ]

A loose example to illustrate this statement:

Assume a normal distribution represents the distance you walk every day. The mean is 5 miles and the standard deviation is 1.01 miles.

What are the chances you will walk exactly 5.53 miles tomorrow? 0. Why? This is where the continuous distribution comes in. Believing there is some chance you walked exactly 5.53 miles that day, you measure the distance on your magic. The ruler reads 5.53 miles, but how do you know it was not 5.531 or 5.529? If you determine it’s definitely between 5.531 and 5.529 on your magic ruler, how do you it’s not 5.5301 or 5.53000000000001? It will never be exactly 5.53. All you can say is that for sure it is between 5.31 and 5.529, and give the probability of that.

Clark
Reply With Quote
  #9  
Old 10-31-2007, 06:15 PM
LarryLaughs LarryLaughs is offline
Member
 
Join Date: Oct 2007
Posts: 47
Default Re: Understanding normal distribution graphs

It may also help to understand that the area below the normal distribution curve is 1. It represents all possible results of a given normally distributed variable. Any single case is an infinitely "thin" slice of the area (along the y-axis direction), which is why there is no real probability of that specific value occuring, just what is the likelihood of a smaller or larger value appearing.
Reply With Quote
Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 10:11 AM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.