#1
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help
I want to know the probability that you lose to a random hand holding AcAd after the flop brings 3 hearts or spades.
also I want to know the same thing but against 2 other players with random hands. knowing this will help me figure out something I will bring up soon. thank you! |
#2
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Re: help
PokerStove is a free tool that answers this type of question well. You can specify a flop and ranges for each player, though not a range of flops such as all monotone flops.
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#3
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Re: help
wow! this thing is pretty cool
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#4
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Re: help
so this program runs thousends of hands played out in one sec? to give a probability
(27,936,562 games/sec) |
#5
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Re: help
Pokerstove gives you pot equity and not probability of winning. In some cases this may cause the probability of winning be like 2% but pot equity will be like 49%, because if the split of the pot.
I do not know any software that does give you the probability of winning. You should determine whether pot equity gives you good estimation instead of probability of winning. |
#6
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Re: help
[ QUOTE ]
Pokerstove gives you pot equity and not probability of winning. In some cases this may cause the probability of winning be like 2% but pot equity will be like 49%, because if the split of the pot. [/ QUOTE ] Actually, PokerStove gives the probability of winning, too. See the text box at the bottom of the window, e.g., <ul type="square"> Text results appended to pokerstove.txt 1,712,304 games 0.032 secs 53,509,500 games/sec Board: Dead: <font color="white">...........</font>equity win tie pots won pots tied Hand 0: 47.508% 02.17% 45.33% 37210 776269.00 { AcKd } Hand 1: 52.492% 07.16% 45.33% 122556 776269.00 { AhKh }[/list] The tie percentage is actually not the percentage of ties, but your equity from ties. |
#7
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Re: help
You are right. It is not that I did not knew it, I am at work...[img]/images/graemlins/crazy.gif[/img]
The probability of a tie is tie equity times total number of players. So in the above example, for Ah Kh: Pr(win) = 7.16% Pr(tie) = 45.33% * 2 players = 90.66% Pr(lose) = 100% - 7.16% - 90.66% = 2.18% (which by definition, equals the probability of player 2 winning) |
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