#1
|
|||
|
|||
quick 6max maths question
If I am dealt a random hand that is not paired, what is the probability that at least one of the other five players was dealt a pair? Anyone know how to figure this out?
|
#2
|
|||
|
|||
Re: quick 6max maths question
The approximate probability is
1- [(1225-78)/1225]^5 ~ 28.03% Read a similar post in the probability forum , titled "full house and quads" for an explanation . |
#3
|
|||
|
|||
Re: quick 6max maths question
my bad. completely forgot probability forum existed. thanks anyway
|
#4
|
|||
|
|||
Re: quick 6max maths question
sorry, new to the site, how can I find the "full house and quads" forum?
thanks |
#5
|
|||
|
|||
Re: quick 6max maths question
Look on the left hand side and click under "General Gambling" . You should be able to see the probability section right underneath it .
|
#6
|
|||
|
|||
Re: quick 6max maths question
Found it, thank you jay
|
|
|