Roulette Edge Question - Page 2

T50_Omaha8 · #11 07-09-2007, 05:50 PM

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why don't you use a strategy in which your odds of winning are greater than 0%

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I don't think any such strategy exists for roulette.

[/ QUOTE ]Ummm...there is a roulette strategy in which your odds of winning exceed 99%.

joel2006 · #12 07-09-2007, 06:05 PM

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why don't you use a strategy in which your odds of winning are greater than 0%

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I don't think any such strategy exists for roulette.

[/ QUOTE ]Ummm...there is a roulette strategy in which your odds of winning exceed 99%.

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And that would be?

kinghippo423 · #13 07-10-2007, 10:44 AM

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Ummm...there is a roulette strategy in which your odds of winning exceed 99%.

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Kids...

rufus · #14 07-10-2007, 01:34 PM

You can generate strategies for any chance to win that is at least zero, and less than one. This is frequently referred to as the 'Martingale' approach to roulette.

Of course, the net EV is still negative.

NickMPK · #15 07-10-2007, 02:38 PM

Your comps will be far less than your expected loss.

But here's what I really don't understand...why would you want to get a hotel room in a casino just so you can stand around a roulette wheel and watch a game that you have zero chance of winning? This sounds like one of the most boring ways to spend a day I can imagine.

kinghippo423 · #16 07-10-2007, 09:37 PM

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Your comps will be far less than your expected loss.

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I dont really understand the meaning of "comps". What is it actually? Do every casino allows it? Thanks in advance.

joel2006 · #17 07-11-2007, 05:12 PM

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Your comps will be far less than your expected loss.

But here's what I really don't understand...why would you want to get a hotel room in a casino just so you can stand around a roulette wheel and watch a game that you have zero chance of winning? This sounds like one of the most boring ways to spend a day I can imagine.

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I will be in the casino anyway playing poker, and if my expected loss is less than the poker rate or would get me rooms on weekends it might be worth it.

T50_Omaha8 · #18 07-11-2007, 09:10 PM

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if my expected loss is less than the poker rate

[/ QUOTE ] Pretty much impossible.

joel2006 · #19 07-13-2007, 12:54 PM

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The EV of any bet in American Roulette is -5.26% of the bet.
Thats the house edge per bet.

EV of $100 bet on the Red or Black:
($100*18/38)+(-$100*20/38)= -$5.26

On average, you and your friend together are expected to lose $10.52 per round, $5.26 each.
So the answer to your question is $1052.

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This doesn't seem right since we only lose half a bet when 0 or 00 comes up. Never mind , I see now it doesn't matter.

metalman7474 · #20 08-19-2007, 07:57 PM

listen up guys! they say no strategy works but let me state otherwise. i use the martingale tech. i start with a bank of lates say $500. i bet $10 on black or red. if i lose , i dbl down until i win. by using $10 as my initial betting, then with a bank of $500, ican afford to dbl downseveral times b 4 my bank is consumed..odds are 7 consecutive colors are not gonna come up in a row.by betting $10, u can lose 5 or 6 in a row but when u dbl down and eventually win, you have won all your money back + $10. so the lesson is to bring a significant bank, so that u can keep dbling down until u win it back. ive never lost using this strategy.sometimes i win $100 other times much more. good luck and test it out 4 yourself.