#1
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Odds of facing AA/KK when you have A/K in Hold\'em
In a fullring texas hold them game, what are the odds that someone else has AA or KK when you hold AK? Thx.
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#2
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Re: Odds of facing AA/KK when you have A/K in Hold\'em
N=number of other players. 3 combos each=6/1326=0.5%
If N=8->8*0.5%=4% More precisely 1-0.995^8 Wanna go all-in with AK? [img]/images/graemlins/wink.gif[/img] |
#3
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Re: Odds of facing AA/KK when you have A/K in Hold\'em
[ QUOTE ]
In a fullring texas hold them game, what are the odds that someone else has AA or KK when you hold AK? Thx. [/ QUOTE ] ~1/20 |
#4
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Re: Odds of facing AA/KK when you have A/K in Hold\'em
50*49/2=1225 (not 52*51/2=1326)
6/1225=0.5% 9 other players->5% |
#5
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Re: Odds of facing AA/KK when you have A/K in Hold\'em
[ QUOTE ]
In a fullring texas hold them game, what are the odds that someone else has AA or KK when you hold AK? Thx. [/ QUOTE ] With 9 opponents: P(AA) = P(KK) = 9*3/C(50,2) = 27/1225 EXACTLY. P(AA or KK) = P(AA) + P(KK) - P(AA and KK) = 27/1225 + 27/1225 - C(9,2)*6/C(50,2)*3/C(48,2) EXACTLY, =~ 21.9-to-1 |
#6
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Re: Odds of facing AA/KK when you have A/K in Hold\'em
if you are worried about being called pf by AA/KK when holding AK, reads on your opponent will be far more helpful than these numbers.
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#7
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Re: Odds of facing AA/KK when you have A/K in Hold\'em
[ QUOTE ]
In a fullring texas hold them game, what are the odds that someone else has AA or KK when you hold AK? Thx. [/ QUOTE ] They are exactly the same as the odds of someone having AA when you have KK. Do you see why? |
#8
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Re: Odds of facing AA/KK when you have A/K in Hold\'em
[ QUOTE ]
[ QUOTE ] In a fullring texas hold them game, what are the odds that someone else has AA or KK when you hold AK? Thx. [/ QUOTE ] They are exactly the same as the odds of someone having AA when you have KK. Do you see why? [/ QUOTE ] They are not exactly the same. The probability of AA or KK when you hold AK is: 9*6/C(50,2) - C(9,2)*6/C(50,2)*3/C(48,2) =~ 4.36% The probability of AA when you hold KK is: 9*6/C(50,2) - C(9,2)*6/C(50,2)*1/C(48,2) =~ 4.39% The slight difference arises from the case where 2 opponents have the hands in question. In the first case, there are still 3 remaining ways for the 2nd opponent to have AA or KK once the first opponent has KK or AA respectively. In the second case, there is only 1 remaining AA when the first opponent has AA. EDIT: I had final numbers reversed. |
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