#1
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Dice Roll Game Problem
Okay I recieved this problem from a friend and we both got different answers when we did it. Ill save my answer for now and see what you guys get. If this is elementary I am sorry.
In this game two dice are rolled. Everytime a 6 is rolled you win $5 and the game starts over. Everytime a 7 is rolled you lose $5 and the game starts over. Every other value no money changes hands and you continue until you roll a 6 or 7. What is the EV per roll, and what is the EV per game, if they are different. Thanks a lot |
#2
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Re: Dice Roll Game Problem
first of all the ev < 0 b/c there are more ways to roll 7 than 6
36 roll combos 6 ways to roll a 7 5 ways to roll a 6 so 5/36 times you win $5 and 6/36 times you lose $5 (5/36)*5 - (6/36)*5= -$5/36 = ~$-0.14 edit: this should probably be in probability. |
#3
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Re: Dice Roll Game Problem
Per Game:
5/11 times the game ends with a 6 and a $5 win 6/11 times the game ends with a 7 and a $5 loss EV/game = (5/11)(5) - (6/11)(5) = -5/11 = -$0.45/game And, it's still Math. |
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