calculating required fold equity in NL hand - is this right?

[vector]

Hi,

I'm trying to work out the % I need opponent to fold to make the following push break even.

If this is wrong can someone help me out with the correct algorithm please?

The hand is heads-up at this decision point.

My hand equity is 38%.
The pot is $224 before my action.
I have $447 remaining.
Opponent covers me.

0ev = 224x + (1-x)(.38*671 - .62*447)
so, x = 22/246 = ~0.09 = ~9%

So if opponent folds > 9% of the time pushing is profitable here.

I think?

Thanks.

[vector]

Too late for edit, realised I made a mistake and didn't provide enough info.

My hand equity is 38%.
The pot is $224 before my action.
Opponent has led for $112 into what was a $112 pot.
(this is counted in the current pot size of $224)
I have $447 remaining.
Opponent covers me.

Since opponent only has to call $319 of my $447 push, it should be:

0ev = 224x + (1-x)(.38*543 - .62*447)
295x = 71
x = 71/295 = 0.24

So in fact he has to fold more than 24% of the time.

Is this right?

Thank you.

[Tiki]

Looks good.

A good link if you are interested in FE and its value.