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  #11  
Old 05-14-2007, 02:42 PM
thirstyforwater thirstyforwater is offline
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Join Date: Feb 2007
Location: Madison, WI
Posts: 151
Default Re: Transitivity with the ladies

[ QUOTE ]
B is the new C.

[/ QUOTE ]

ha ha, well played
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  #12  
Old 05-14-2007, 02:47 PM
cwes cwes is offline
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Join Date: Mar 2005
Location: BOOK IT
Posts: 878
Default Re: Transitivity with the ladies

[ QUOTE ]
And will you post pics?

[/ QUOTE ]
As always Pooptoad is spot on in seeing this as it is: Just another girl problem thread w/o pics.

Hail thee, holy Pooptoad!
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  #13  
Old 05-14-2007, 02:54 PM
KAknight KAknight is offline
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Join Date: Jul 2005
Location: Tulsa, OK
Posts: 513
Default Re: Transitivity with the ladies

It means you should have some hot man on man lovin with friend A.
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  #14  
Old 05-14-2007, 04:02 PM
findingneema findingneema is offline
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Join Date: Feb 2007
Location: San Francisco, CA
Posts: 684
Default Re: Transitivity with the ladies

I think not, inequalities here instead of equalities (i.e. if A bangs C, that means A >= C on some sort of sexing scale).

A >= C
B >= C
A >= D

B >= D ??? not necessarily

Don't count your sloppy seconds until you actually SIIHP.
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  #15  
Old 05-14-2007, 04:23 PM
Jeff_B Jeff_B is offline
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Join Date: Jul 2005
Location: I need Patience NOW
Posts: 2,846
Default Re: Transitivity with the ladies

if (Friend A + chick C) = F and (You + chick C) = F then it follows that

(Friend A + chick C) + (You + chick C) = 2F
factoring out chick C
we get

chick C(Friend A + You) = 2F
since chick C is constant we can go ahead and remove her from the equation...
so

Friend A + You = 2F ....

not that there is anything wrong with that
whether its just once or twice...
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  #16  
Old 05-14-2007, 04:24 PM
ikestoys ikestoys is offline
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Join Date: Nov 2006
Location: I\'m not folding, stop bluffing
Posts: 5,642
Default Re: Transitivity with the ladies

i have a friend like this, we call him the scavenger
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  #17  
Old 05-14-2007, 04:30 PM
pooptoad pooptoad is offline
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Join Date: Apr 2007
Posts: 98
Default Re: Transitivity with the ladies

[ QUOTE ]
if (Friend A + chick C) = F and (You + chick C) = F then it follows that

(Friend A + chick C) + (You + chick C) = 2F
factoring out chick C
we get

chick C(Friend A + You) = 2F
since chick C is constant we can go ahead and remove her from the equation...
so

Friend A + You = 2F ....

not that there is anything wrong with that
whether its just once or twice...

[/ QUOTE ]

This reminds me of this... OMG, false proof!
Step 1: Let a=b.
Step 2: Then , a^2 = a*b
Step 3: a^2 + a^2 = a^2 + a*b
Step 4: 2*a^2 = a^2 + a*b
Step 5: 2*a^2 - 2*a*b = a^2 + a*b - 2*a*b
Step 6: 2*a^2 - 2*a*b = a^2 - a*b
Step 7: This can be written as 2*(a^2 - a*b) = 1(a^2 - a*b)
Step 8: and cancelling the (a^2 - a*b) from both sides gives 1=2.
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  #18  
Old 05-14-2007, 04:33 PM
Jeff_B Jeff_B is offline
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Join Date: Jul 2005
Location: I need Patience NOW
Posts: 2,846
Default Re: Transitivity with the ladies

lol pooptoad went to college but yeah in calculus you can drop all the constants +c and well if I didn't do that OP doesn't have the meaningful relationship he truly wants with his friend
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  #19  
Old 05-14-2007, 04:34 PM
cwes cwes is offline
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Join Date: Mar 2005
Location: BOOK IT
Posts: 878
Default Re: Transitivity with the ladies

[ QUOTE ]

Step 1: Let a=b.
.
.
.
Step 7: This can be written as 2*(a^2 - a*b) = 1(a^2 - a*b)
Step 8: and cancelling the (a^2 - a*b) from both sides gives 1=2.

[/ QUOTE ]
If you can divide by (a^2 - a*b), u sure can make 1 equal 2.
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  #20  
Old 05-14-2007, 04:44 PM
pooptoad pooptoad is offline
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Join Date: Apr 2007
Posts: 98
Default Re: Transitivity with the ladies

[ QUOTE ]

If you can divide by (a^2 - a*b), u sure can make 1 equal 2.

[/ QUOTE ]

NERD!!!
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