Suited cards 10 or better 10 handed game

[aroddolla]

Is there a 30% chance some one will hold suited cards 10 or better in a ten handed game? If you answer this brucez and my calculation is too high, and you use the combinitronics method can you show the math so I can learn this and stop asking these questions, thanks. I dont know how to compute 1-C(X,X)/(X,X) or what ever the formula is.

[Haagen]

Probability for 1 person having 2 cards greater than 10 that are suited is 4/13 * 3/51 (pick any card greater than 10 of any suit's probability (4/13) and multiply it by the chance of another card of that suit greater than 10 /cards in the deck).

p = 4/13 * 3/51. This is a Binomial RV. so we want to know when no one has it. so it's (10c0)(p)^0(1-p)^10. Basically it's (1-p)^10.