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#1
02-09-2007, 11:04 PM
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3 Players at Same Table in In Large Tourny
Me and two of my friends joined a multi table tournament on Pokerstars and all 3 of us started at the same table. There were 889 entrants including us (9 players/table) What are the odds of this?
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#2
02-09-2007, 11:38 PM
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Re: 3 Players at Same Table in In Large Tourny
[ QUOTE ]
Me and two of my friends joined a multi table tournament on Pokerstars and all 3 of us started at the same table. There were 889 entrants including us (9 players/table) What are the odds of this? [/ QUOTE ] Assuming that you are each independently seated at one of 889 equally likely seats on 97 tables of 9 plus 2 tables of 8, the probability that you will all be at the same table is [97*C(9,3)+2*C(8,3)] / C(889,3) =~ 1 in 14,129.
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#3
02-11-2007, 12:40 AM
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Re: 3 Players at Same Table in In Large Tourny
A more simply explanation, though not as exact is...
Given that Player 1 is already sat at a 9 person table, then the odds of player 2 being at same table is 8/888 and Player 3 is then 7/887 . When you multiply this out, you get about 1/14065. The slight difference between this and the previous answer might be the small chance that Player 1 is sat at the 8 person table.
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#4
02-11-2007, 06:41 AM
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Re: 3 Players at Same Table in In Large Tourny
[ QUOTE ]
A more simply explanation, though not as exact is... Given that Player 1 is already sat at a 9 person table, then the odds of player 2 being at same table is 8/888 and Player 3 is then 7/887 . When you multiply this out, you get about 1/14065. The slight difference between this and the previous answer might be the small chance that Player 1 is sat at the 8 person table. [/ QUOTE ] Correct, and that can be made exact like this: (873/889 * 8/888 * 7/887) + (16/889 * 7/888 * 6/887) =~ 1 in 14,129.
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