#1
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math help
anyone solve this?
4/(x-4) + 3/(x+4) = 5/ xsquared = 16 solve for x |
#2
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Re: math help
it has two equals signs in it
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#3
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Re: math help
well ... were is your god when you need him?
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#4
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Re: math help
someone posted this on a diiferent forum and it didnt make sense to me either, just thought some of the very intelligent folks at 2+2 might be able to figure it out...
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#5
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Re: math help
There is clearly an error in the equation. If 5/x^2 is equal to 16 then x is equal to Sqrt(5/16). If you plug that value into the left side it is not equal to 16 therefore there is either no solution or someone made a mistake typing the equation.
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#6
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Re: math help
[ QUOTE ]
anyone solve this? 4/(x-4) + 3/(x+4) = 5/ xsquared = 16 solve for x [/ QUOTE ] It probably was supposed to be 4/(x-4) + 3/(x+4) = 5/(x^2-16). That makes it an easily solveable middle-school-Algebra-text-like problem. (The answer would be x = 1/7, BTW.) |
#7
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Re: math help
[ QUOTE ]
anyone solve this? 4/(x-4) + 3/(x+4) = 5/ xsquared = 16 solve for x [/ QUOTE ] Assuming the problem is actually... 4/(x-4) + 3/(x+4) = 5/(x^2-16) 1) Make the common denominator x^2-16 by multiplying the first fraction by (x+4)/(x+4) and the second by (x-4)/(x-4) 4(x+4)/(x-4)(x+4) + 3(x-4)/(x-4)(x+4) = 5/(x^2-16) 4x+16/(x^2-16) + 3x-12/(x^2-16) = 5/(x^2-16) 2) Drop denominators and simplify 4x+16 + 3x-12 = 5 7x + 4 = 5 7x = 1 x = 1/7 (as the other poster said) |
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