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| View Poll Results: HOW FAT IS U | |||
| REAL FAT |
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15 | 4.09% |
| 130-150lbs overweight |
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12 | 3.27% |
| 110-130lbs |
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6 | 1.63% |
| 90-110lbs |
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4 | 1.09% |
| 70-90lbs |
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4 | 1.09% |
| 60-70lbs |
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2 | 0.54% |
| 50-60lbs |
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5 | 1.36% |
| 40-50lbs |
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12 | 3.27% |
| 30-40lbs |
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20 | 5.45% |
| 20-30lbs |
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29 | 7.90% |
| 10-20lbs |
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54 | 14.71% |
| 0-10lbs |
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66 | 17.98% |
| im in shape (lie) |
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84 | 22.89% |
| . |
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9 | 2.45% |
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5 | 1.36% |
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11 | 3.00% |
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8 | 2.18% |
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9 | 2.45% |
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4 | 1.09% |
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8 | 2.18% |
| Voters: 367. You may not vote on this poll | |||
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Thread Tools | Display Modes |
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#1
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To get started I'm going to pose a hypothetical.
Fred Astaire is always right. He never makes a mistake. If you give him a problem that he can solve, he will solve it correctly 100% of the time. But Fred can't handle differential equations. Starting somewhere around basic calculus, he just can't wrap his mind around the problem. Fred's a logical person, he's right where all of the common-sense stuff is concerned, and he's a great poker player. Ginger Rogers makes mistakes. She makes lots of mistakes. In fact, in every problem she tries to solve, she has a 50% chance of [censored] up. What's 3+3? "7." What's the largest mammal? "The shrew." How many fingers am I holding up? "Erk - NaN." But Ginger can handle any kind of problem. She consistently scores 60 on the Putnam exam, and if she sets out to prove the Goldbach conjecture, she has a 50% chance of success. Yes, no matter what the problem is, Ginger has a 50% chance of solving it. Ginger is often seen as irrational due to her mistakes, and she frequently hemorrhages money in poker. So, who's smarter? |
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#2
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madnak, Ginger of course. Everyone knows Ginger did everything Fred did in heels going backwards. [img]/images/graemlins/grin.gif[/img]
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#3
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Ginger is an impossibility.
It would take a parlay of many 50% error free steps (on 3+3 =7 type ones) for her to solve difficult problems. D |
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#4
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I voted fred, since there's so much he is infallible on. If you increase Ginger's chance of success to 80% or something it gets harder for me.
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#5
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I don't think its even close. Because Ginger never knows if she's right.
For Ginger to exist, she cannot be aware of her limitations. |
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#6
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[ QUOTE ]
Ginger is an impossibility. It would take a parlay of many 50% error free steps (on 3+3 =7 type ones) for her to solve difficult problems. D [/ QUOTE ] this is why i couldn't vote. |
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#7
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Ginger appears to be some sort of freakish idiot savant.
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#8
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[ QUOTE ]
Ginger appears to be some sort of freakish idiot savant. [/ QUOTE ] ROFL [img]/images/graemlins/laugh.gif[/img] |
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#9
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Fred is smarter because he's more likely to know his limitations on what problems he is qualified to weigh in on with certainty.
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#10
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[ QUOTE ]
[ QUOTE ] Ginger is an impossibility. It would take a parlay of many 50% error free steps (on 3+3 =7 type ones) for her to solve difficult problems. D [/ QUOTE ] this is why i couldn't vote. [/ QUOTE ] It's a hypothetical. Suspend this. How she solves the problems is irrelevant, it's the results that matter. |
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