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  #41  
Old 04-10-2005, 10:59 PM
Mroberts3 Mroberts3 is offline
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Default Re: \"How many hands do I need to play...\"

ok, i must be computer illerate. once I have the numbers plugged in, how do i get excel to perform the operation? (for someone whos uses comps as much as I do i cant believe i can not find out how, lol)
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  #42  
Old 04-28-2005, 08:45 AM
PokerBob PokerBob is offline
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Default Re: \"How many hands do I need to play...\"

[ QUOTE ]
ev - normsinv[(1-c)/2]*sd*[1/sqrt(n)]

l = ev + normsinv[(1-c)/2]*sd*[1/sqrt(n)]



[/ QUOTE ]

I'm trying to crunch these numbers. Can someone tell me what "normsinv" is?
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  #43  
Old 04-28-2005, 09:05 AM
Baulucky Baulucky is offline
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Default Re: \"How many hands do I need to play...\"

[ QUOTE ]
I'm trying to crunch these numbers. Can someone tell me what "normsinv" is?

[/ QUOTE ]

An Excel statistic function fully explained in the help section of said program.
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  #44  
Old 04-28-2005, 09:12 AM
PokerBob PokerBob is offline
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Default Re: \"How many hands do I need to play...\"

[ QUOTE ]
[ QUOTE ]
I'm trying to crunch these numbers. Can someone tell me what "normsinv" is?

[/ QUOTE ]

An Excel statistic function fully explained in the help section of said program.

[/ QUOTE ]

So I guess I can't do this with my calculator???
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  #45  
Old 04-28-2005, 09:26 AM
obsidian obsidian is offline
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Default Re: \"How many hands do I need to play...\"

[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
I'm trying to crunch these numbers. Can someone tell me what "normsinv" is?

[/ QUOTE ]

An Excel statistic function fully explained in the help section of said program.

[/ QUOTE ]

So I guess I can't do this with my calculator???

[/ QUOTE ]
Nope. But you could go look it up in a z-score table. If your confidence interval is 95%, you take (1-0.95)/2, or 0.025, subtract it from 1 to get .975, and then look for .975 in the table. In this case, it is 1.96.
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  #46  
Old 04-28-2005, 09:46 AM
obsidian obsidian is offline
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Default Re: \"How many hands do I need to play...\"

I'm not sure if this is new (don't remember seeing it before) but PT also offers SD/100 hands. So would this equation work as well?

BB/100 hands +/- NORMSINV((1-confidence)/2) * SD/100 * 1/SQRT(hands/100)
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  #47  
Old 04-28-2005, 01:22 PM
mindflayer mindflayer is offline
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Default Re: \"How many hands do I need to play...\"

A monkey in the zoo thanks YOU! for this thread.
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  #48  
Old 04-28-2005, 01:29 PM
Josh. Josh. is offline
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Default Re: \"How many hands do I need to play...\"

Homer puts my stat posts to shame [img]/images/graemlins/frown.gif[/img]
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  #49  
Old 05-26-2005, 12:47 PM
ryanflies ryanflies is offline
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Default Re: \"How many hands do I need to play...\"

btw, I uploaded the spreadsheet to an htm. http://e.sixbit.org/howmanyhands.htm

according to my numbers at $1/2:

hours (PT) 7.38
wr/hr (PT) in $ 12.33
sd/hr (PT) in $ 14.1601
confidence (PT) 0.95

I'm 95% confident that my wr is between $22.54612576/hr and $2.113874238/hr.

That doesn't seem right with such a small sample. Is it?
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  #50  
Old 07-19-2005, 09:49 PM
Dan (Theman) Dan (Theman) is offline
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Default Re: \"How many hands do I need to play...\"

I think that is because your SD is no where near accurate after 7 hours. You have been running well with a low SD so far. Your SD will probably rise.
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