theoretical heads-up question

[ezratei]

you are playing a NLHE shoot-out heads up against a computer. You can only play one shoot-out and then the computer will explode. The computer is programmed to go all-in preflop every hand. Blinds are $0.5/$1. You both start with stack-size $X.

First hand: You are BB and dealt KK ... computer goes all-in.

At what stack-size X is folding correct?

[Gary Stevenson]

7,214.92

[eso]

Put KK vs atc into an odds checker. Take answer and use in combination with your bankroll and put figures into Kelly's (whatever the risk of ruin formula is) formula. Answer is X.

[Jackal69]

Macgyver says 217.5bb

[AZK]

infinity?

[kitaristi0]

I guess I don't understand the question or am just exceptionally thick but I would never fold.

[Dr. Strangelove]

When the value of the blinds you will lose waiting for AA is less than the difference in equity between the AA v random hand and KK v random hand matchup multiplied by the average stack you will have after the blinding down.

You'll also have to figure your odds of winning versus this average blinding off value, so you'll need a strategy there also.

[Dr. Strangelove]

Using pokerstove:
AAv random= 85.2 : 14.8
KKv random= 82.4 : 17.6

the difference in equity is 2.8%. On average it takes 221 hands to pick up aces, you blind off $.75 per hand.

221*.75= 165.75

165.75=.028x
x=5919

The break even point should be around 100 blinds higher, plus or minus a couple, because you will still lose sometimes even with the gigantic chip lead. So you should fold KK preflop here if you are 6000 big blinds deep or more. Barring some retarded mistake i made in the math.

I'm pretty tired, maybe I should be thinking of the 2.8% difference as a percentage increase of 82.4%?

[ddrstel]

isnt this a sklansky-chubakov number answer?

[ahnuld]

this is obviously too deep for the HSNL forum. Maybe ask a mod to move it to the special sklansky forum? Perfect for there.