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#1
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Re: probability homework question
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Hi Bruce - I didn't solve it for the specific example, but for the general case when hero has trips with one card higher and one card lower. [/ QUOTE ] I understand. I didn't just solve it just for the example either, I solved it for the question which I believe was asked, which is for any 3-of-a-kind where the other 2 cards are one RANK above and one RANK below. While the words RANK were not present in the problem statement, I am pretty sure that is what was intended as I simply don't believe that your interpretation, which is "the other two cards consist of one higher and one lower card", is correctly expressed in English by the words "the other two cards are one above and one below". Gene Fish, please tell us which interpretation you intended. |
#2
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Re: probability homework question
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one RANK above and one RANK below [/ QUOTE ]Hi Bruce - I see another way to read the problem that I had not even considered before. 222A3, 33324, 44435, etc. (but not 44436 or 44425 or 44426 etc.) just exactly one rank above the trips and exactly one rank below the trips. Interesting. Thanks. I'm going back to Omaha now. Buzz |
#3
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Re: probability homework question
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I see another way to read the problem that I had not even considered before. 222A3, 33324, 44435, etc. (but not 44436 or 44425 or 44426 etc.) just exactly one rank above the trips and exactly one rank below the trips. [/ QUOTE ] That was my interpretation. Pococurante's too. |
#4
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Re: probability homework question
guys...thank you so much for the response...bruce...you hit it perfect...dunno why my brain didn't think of that - seems kinda simple when you lay it out.
this forum is the best! thanks again |
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