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#1
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Classical Chinese 2-7 Choice
One kind of hand that comes very often in Chinese Poker 2-7 is this type of hand:
JJJTTAAK22689 and you have to decide between: A: JJJTT K9862 AA2 B: JJJTT 22986 AAK Which one do you think is stronger? What about if we replace 22 for 33 or 44 or 55? |
#2
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Re: Classical Chinese 2-7 Choice
How about JJJ22 689TK AAT? That provides the same strength in back, a pair-free middle, and a front nearly as strong as AAK (especially since you hold two T's and three J's.)
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#3
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Re: Classical Chinese 2-7 Choice
I ran the calculator; the following three options are pretty close.
Sample error might switch things, these numbers are _not_ accurate to six figures! I would only trust about two digits (+/- 0.03 I think is a reasonable estimate), each hand has about 12K-13K samples. JJJTT 22689 AAK: +1.01977 JJJTT 2689K AA2: +1.02526 JJJ22 689TK AAT: +1.08465 Here are a couple similar hands: QQQTT 33689 AAK: +1.23931 QQQTT 3689K AA3: +1.26218 QQQ33 689TK AAT: +1.33393 TTT99 44678 AAK: +0.720626 TTT99 4678K AA4: +0.851657 TTT44 6789K AA9: +0.888801 |
#4
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Re: Classical Chinese 2-7 Choice
Since I created this hand I overlooked that possibility, let me correct it:
JJJ3322689AAK: This one is more interesting. The main thing is to find out what is more important, the kicker or no pair in the middle. |
#5
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Re: Classical Chinese 2-7 Choice
It's very close (possibly within the range of error of this experiment), but I think on balance you should prefer to play an upaired hand in the middle.
22JJJ 3689K 3AA: +1.06765 33JJJ 2689K 2AA: +1.06593 33JJJ 22689 KAA: +1.02294 |
#6
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Re: Classical Chinese 2-7 Choice
No wonder is such a difficult decision for everybody. I asked many good players about this play and nobody was sure how to play it. I wonder if you have to use psychology to set this hand.
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