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  #1  
Old 11-17-2007, 08:34 AM
fatshark fatshark is offline
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Default Re: Bad Beat Jackpots = Zero Sum?

[ QUOTE ]
[ QUOTE ]
Gaming regulations prohibit them from raking more than 10% from a game, and raking the BBJ/HHJ drop would put 'em over 10%.

[/ QUOTE ]

Wouldn't that only be true if the $1 that constitutes the jackpot drop is also counted toward the raked pot?

For example, take a 1/2NL game with a 10% to $4 rake. The last dollar is taken out at $40, and the jackpot drop is taken out at $20.

Consider a gross pot of $40. $1 got taken out for the jackpot at $20, leaving $39. Only $3 got taken out for rake, because pot after jackpot drop < $40. Total rake is $3 + $.10 that will be raked from the jackpot. $3.10 < 10% * $40.

Now consider a gross pot of $41. $1 got taken out for the jackpot at $20, leaving $40. As a result, $4 was raked from the pot. Total rake is $4 + $.10 on the jackpot. $4.10 = 10% * $41.

[/ QUOTE ]

On a pot of $35 or more, the house rounds up and the rake would be $4. So the information is not correct.
The BBJ collection can be taken at what ever the house decides is a qualifying pot.
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  #2  
Old 11-17-2007, 08:40 AM
bav bav is offline
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Default Re: Bad Beat Jackpots = Zero Sum?

[ QUOTE ]
On a pot of $35 or more, the house rounds up and the rake would be $4.

[/ QUOTE ]
Uhhhh... Not even slightly true in Nevada. They CANNOT rake more than 10% ever, and they don't get to round. They rake $3 at $39, $4 at $40. I believe Posh got it completely right.
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  #3  
Old 11-17-2007, 10:04 AM
fatshark fatshark is offline
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Join Date: Nov 2006
Posts: 102
Default Re: Bad Beat Jackpots = Zero Sum?

[ QUOTE ]
[ QUOTE ]
On a pot of $35 or more, the house rounds up and the rake would be $4.

[/ QUOTE ]
Uhhhh... Not even slightly true in Nevada. They CANNOT rake more than 10% ever, and they don't get to round. They rake $3 at $39, $4 at $40. I believe Posh got it completely right.

[/ QUOTE ]
Really, thanks for that, I had no idea. The few times I spot checked to confirm that I guess the dealers got a little "pinchy"!
How about the commission/service charge on player's pools? can they do that too in NV?
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  #4  
Old 11-17-2007, 11:21 AM
Al_Capone_Junior Al_Capone_Junior is offline
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Join Date: Feb 2003
Location: utility muffin research kitchen
Posts: 5,766
Default Re: Bad Beat Jackpots = Zero Sum?

[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
Gaming regulations prohibit them from raking more than 10% from a game, and raking the BBJ/HHJ drop would put 'em over 10%.

[/ QUOTE ]

Wouldn't that only be true if the $1 that constitutes the jackpot drop is also counted toward the raked pot?

For example, take a 1/2NL game with a 10% to $4 rake. The last dollar is taken out at $40, and the jackpot drop is taken out at $20.

Consider a gross pot of $40. $1 got taken out for the jackpot at $20, leaving $39. Only $3 got taken out for rake, because pot after jackpot drop < $40. Total rake is $3 + $.10 that will be raked from the jackpot. $3.10 < 10% * $40.

Now consider a gross pot of $41. $1 got taken out for the jackpot at $20, leaving $40. As a result, $4 was raked from the pot. Total rake is $4 + $.10 on the jackpot. $4.10 = 10% * $41.

[/ QUOTE ]

On a pot of $35 or more, the house rounds up and the rake would be $4. So the information is not correct.
The BBJ collection can be taken at what ever the house decides is a qualifying pot.

[/ QUOTE ]

With 10% to $4 + $1 for the jackpot taken at $20, a $40 pot would have $4 in rake, $1 jackpot, and $35 available to win by the players. This is very much standard, all rake and jackpot dollars count towards total pot size. If there were only $20 in the pot, $2 is for rake, $1 for jackpot, and $17 available to win by players.

There is no rounding up. A $19 pot takes $1 in rake ** and nothing for the jackpot because it does not qualify. Rounding up would exceed the 10% max.

Al

** assumes there is no breakage below $1 chips, i.e. no coin is used
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  #5  
Old 11-17-2007, 12:05 PM
psandman psandman is offline
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Join Date: Sep 2005
Location: Vegas
Posts: 2,346
Default Re: Bad Beat Jackpots = Zero Sum?

[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
Gaming regulations prohibit them from raking more than 10% from a game, and raking the BBJ/HHJ drop would put 'em over 10%.

[/ QUOTE ]

Wouldn't that only be true if the $1 that constitutes the jackpot drop is also counted toward the raked pot?

For example, take a 1/2NL game with a 10% to $4 rake. The last dollar is taken out at $40, and the jackpot drop is taken out at $20.

Consider a gross pot of $40. $1 got taken out for the jackpot at $20, leaving $39. Only $3 got taken out for rake, because pot after jackpot drop < $40. Total rake is $3 + $.10 that will be raked from the jackpot. $3.10 < 10% * $40.

Now consider a gross pot of $41. $1 got taken out for the jackpot at $20, leaving $40. As a result, $4 was raked from the pot. Total rake is $4 + $.10 on the jackpot. $4.10 = 10% * $41.

[/ QUOTE ]

On a pot of $35 or more, the house rounds up and the rake would be $4. So the information is not correct.
The BBJ collection can be taken at what ever the house decides is a qualifying pot.

[/ QUOTE ]

With 10% to $4 + $1 for the jackpot taken at $20, a $40 pot would have $4 in rake, $1 jackpot, and $35 available to win by the players. This is very much standard, all rake and jackpot dollars count towards total pot size. If there were only $20 in the pot, $2 is for rake, $1 for jackpot, and $17 available to win by players.

There is no rounding up. A $19 pot takes $1 in rake ** and nothing for the jackpot because it does not qualify. Rounding up would exceed the 10% max.

Al

** assumes there is no breakage below $1 chips, i.e. no coin is used

[/ QUOTE ]

Last night while dealing at a casino with a relatively cheap rake (10%, $3 Max, Jackpot $1 on $20) I had a player complaining about the rake point to the drop slot and announce "That's the Second Most Expensive Hole in the World"
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  #6  
Old 11-17-2007, 12:38 PM
Al_Capone_Junior Al_Capone_Junior is offline
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Join Date: Feb 2003
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Default Re: Bad Beat Jackpots = Zero Sum?

He aint played at a harrahs joint lately, has he :-/

Al
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