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#1
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Re: Bad Beat Jackpots = Zero Sum?
[ QUOTE ]
[ QUOTE ] Gaming regulations prohibit them from raking more than 10% from a game, and raking the BBJ/HHJ drop would put 'em over 10%. [/ QUOTE ] Wouldn't that only be true if the $1 that constitutes the jackpot drop is also counted toward the raked pot? For example, take a 1/2NL game with a 10% to $4 rake. The last dollar is taken out at $40, and the jackpot drop is taken out at $20. Consider a gross pot of $40. $1 got taken out for the jackpot at $20, leaving $39. Only $3 got taken out for rake, because pot after jackpot drop < $40. Total rake is $3 + $.10 that will be raked from the jackpot. $3.10 < 10% * $40. Now consider a gross pot of $41. $1 got taken out for the jackpot at $20, leaving $40. As a result, $4 was raked from the pot. Total rake is $4 + $.10 on the jackpot. $4.10 = 10% * $41. [/ QUOTE ] On a pot of $35 or more, the house rounds up and the rake would be $4. So the information is not correct. The BBJ collection can be taken at what ever the house decides is a qualifying pot. |
#2
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Re: Bad Beat Jackpots = Zero Sum?
[ QUOTE ]
On a pot of $35 or more, the house rounds up and the rake would be $4. [/ QUOTE ] Uhhhh... Not even slightly true in Nevada. They CANNOT rake more than 10% ever, and they don't get to round. They rake $3 at $39, $4 at $40. I believe Posh got it completely right. |
#3
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Re: Bad Beat Jackpots = Zero Sum?
[ QUOTE ]
[ QUOTE ] On a pot of $35 or more, the house rounds up and the rake would be $4. [/ QUOTE ] Uhhhh... Not even slightly true in Nevada. They CANNOT rake more than 10% ever, and they don't get to round. They rake $3 at $39, $4 at $40. I believe Posh got it completely right. [/ QUOTE ] Really, thanks for that, I had no idea. The few times I spot checked to confirm that I guess the dealers got a little "pinchy"! How about the commission/service charge on player's pools? can they do that too in NV? |
#4
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Re: Bad Beat Jackpots = Zero Sum?
[ QUOTE ]
[ QUOTE ] [ QUOTE ] Gaming regulations prohibit them from raking more than 10% from a game, and raking the BBJ/HHJ drop would put 'em over 10%. [/ QUOTE ] Wouldn't that only be true if the $1 that constitutes the jackpot drop is also counted toward the raked pot? For example, take a 1/2NL game with a 10% to $4 rake. The last dollar is taken out at $40, and the jackpot drop is taken out at $20. Consider a gross pot of $40. $1 got taken out for the jackpot at $20, leaving $39. Only $3 got taken out for rake, because pot after jackpot drop < $40. Total rake is $3 + $.10 that will be raked from the jackpot. $3.10 < 10% * $40. Now consider a gross pot of $41. $1 got taken out for the jackpot at $20, leaving $40. As a result, $4 was raked from the pot. Total rake is $4 + $.10 on the jackpot. $4.10 = 10% * $41. [/ QUOTE ] On a pot of $35 or more, the house rounds up and the rake would be $4. So the information is not correct. The BBJ collection can be taken at what ever the house decides is a qualifying pot. [/ QUOTE ] With 10% to $4 + $1 for the jackpot taken at $20, a $40 pot would have $4 in rake, $1 jackpot, and $35 available to win by the players. This is very much standard, all rake and jackpot dollars count towards total pot size. If there were only $20 in the pot, $2 is for rake, $1 for jackpot, and $17 available to win by players. There is no rounding up. A $19 pot takes $1 in rake ** and nothing for the jackpot because it does not qualify. Rounding up would exceed the 10% max. Al ** assumes there is no breakage below $1 chips, i.e. no coin is used |
#5
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Re: Bad Beat Jackpots = Zero Sum?
[ QUOTE ]
[ QUOTE ] [ QUOTE ] [ QUOTE ] Gaming regulations prohibit them from raking more than 10% from a game, and raking the BBJ/HHJ drop would put 'em over 10%. [/ QUOTE ] Wouldn't that only be true if the $1 that constitutes the jackpot drop is also counted toward the raked pot? For example, take a 1/2NL game with a 10% to $4 rake. The last dollar is taken out at $40, and the jackpot drop is taken out at $20. Consider a gross pot of $40. $1 got taken out for the jackpot at $20, leaving $39. Only $3 got taken out for rake, because pot after jackpot drop < $40. Total rake is $3 + $.10 that will be raked from the jackpot. $3.10 < 10% * $40. Now consider a gross pot of $41. $1 got taken out for the jackpot at $20, leaving $40. As a result, $4 was raked from the pot. Total rake is $4 + $.10 on the jackpot. $4.10 = 10% * $41. [/ QUOTE ] On a pot of $35 or more, the house rounds up and the rake would be $4. So the information is not correct. The BBJ collection can be taken at what ever the house decides is a qualifying pot. [/ QUOTE ] With 10% to $4 + $1 for the jackpot taken at $20, a $40 pot would have $4 in rake, $1 jackpot, and $35 available to win by the players. This is very much standard, all rake and jackpot dollars count towards total pot size. If there were only $20 in the pot, $2 is for rake, $1 for jackpot, and $17 available to win by players. There is no rounding up. A $19 pot takes $1 in rake ** and nothing for the jackpot because it does not qualify. Rounding up would exceed the 10% max. Al ** assumes there is no breakage below $1 chips, i.e. no coin is used [/ QUOTE ] Last night while dealing at a casino with a relatively cheap rake (10%, $3 Max, Jackpot $1 on $20) I had a player complaining about the rake point to the drop slot and announce "That's the Second Most Expensive Hole in the World" |
#6
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Re: Bad Beat Jackpots = Zero Sum?
He aint played at a harrahs joint lately, has he :-/
Al |
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