#1
|
|||
|
|||
Math quesion
I'm reading Hilger's Texas Hold'em odds and probabilities and can't get some of the calculations to work out. For example....
The odds of getting dealt Aces twice in a row is 0.0045 x 0.0045 = 0.00002. (all well and good so far). The part I don't get is where he works out the odds by taking the inverse and subtracting 1 giving 49,383 to 1. When I do that calculation I get 49,999. Where am I going wrong? With other calculations it seems to work out fine (i.e. if the probability of something happening is 0.02 then 1/.02 - 1 = 49 to 1) |
|
|