Quick math question

[jono]

Assume 6 max 6 handed, if a player folds their blinds 100% of the time, what will their pokertracker BB per HAND be in those positions?

We'll say they're a blind 1/3 of the time, so 33x with an average 100 hands, loss of (1 + .5) / 2 big blinds = .75 x 33 = 24.75 big blinds lost. So this = 12.37 BB lost per 100 hands right? Which means - .124 pokertracker BB/HAND lost

correct?

[jstill]

well this is kinda a weird question cuz people will get AA KK QQ and other hands they ll definitely play regularly, but if someone folds their sb 100% of the time their BB lost per hand will be whatever the structure is so in a one third like .33 so BB/100 would be 100 times that obviously or 33 bb/100... fold BB 100% of the time -100bb/100 obviously (this per hundred are not per hundred hands total at the table they are per hundred hands played in that position).

[Dean Moriarty]

You'll lose 0.5 ptbb/hand from the bb, 0.25 ptbb/hand from the sb, so (0.5+0.25)/6 = 0.125 ptbb/hand total, it's that simple!

(your deviation comes from the fact that 1/3 * 100 does not equal 33)

[drzen]

[ QUOTE ]
well this is kinda a weird question cuz people will get AA KK QQ and other hands they ll definitely play regularly

[/ QUOTE ]

Yes, but I think OP is probably trying to work this out so that he can consider it "par", IYKWIM.