Two Plus Two Newer Archives  

Go Back   Two Plus Two Newer Archives > General Gambling > Sports Betting
FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
  #1  
Old 11-18-2007, 03:01 AM
mickeyg13 mickeyg13 is offline
Member
 
Join Date: Sep 2007
Posts: 70
Default NBA True Winning Percentage

I know it's been studied in baseball that looking at run differential can be a more accurate predictor of future winning percentage than even current winning percentage (some form of Pythagorean wins). Has anyone studied anything similar in the NBA? This might have an obvious answer, but I'm not as much of an NBA fan as I am MLB, but the NBA seems to be the only other major sport where sample size issues wouldn't trivialize findings.
Reply With Quote
  #2  
Old 11-18-2007, 03:29 AM
Dudd Dudd is offline
Senior Member
 
Join Date: Sep 2004
Posts: 3,048
Default Re: NBA True Winning Percentage

[ QUOTE ]
Pythagorean winning percentage - A Bill James invention in baseball, Pythagorean records are based on the knowledge that team winning percentages are generally closely related to points scored and points allowed (and, in cases where they differ, the reason is usually temporary luck). This relationship can be approximated by PF^x/((PF^x) + (PA^x), where x depends on the total points scored. In baseball, over the course of a season, x is close enough to be approximated by two. In basketball, x is a little more difficult to calculate. When Oliver did it a decade and a half ago, it was about 16.5. Now, because point totals are lower, the exponent is believed to be closer to 13 or 14. It is also possible to calculate Pythagorean percentages in different ways, like a multiplier (2.7) by the team's point differential (for an 82-game season). This is slightly less accurate, but much easier. A third, more complicated method is employed by Oliver, which takes into account the variability in a team's points scored or points allowed and is thus more accurate.
Statistically: PF^13.5/((PF^13.5)+(PA^13.5))
Expected wins = 2.7*(PF/G-PA/G) + 41

[/ QUOTE ]

From here
Reply With Quote
  #3  
Old 11-18-2007, 09:39 AM
mogwai316 mogwai316 is offline
Senior Member
 
Join Date: Aug 2007
Posts: 266
Default Re: NBA True Winning Percentage

You can see the updated values of this stat every day in the expected W-L and WP columns here:
http://sports.espn.go.com/nba/stats/rpi

It does use the 16.5 exponent value. You could easily compute the numbers using a different exponent if you want, though.
Reply With Quote
Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 09:54 AM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.