Prob. of getting 2 pr. in 5 card draw poker?

[mdb]

Sklansky says that the prob. of being dealt 2 pr. in 5 card draw is 5% on p. 229 of The Theory of Poker.
My math: {3/50 *3/49 *44/48 *43/47 * 42/46}*5! doesn't work.
Does anyone know the correct equation?

[bigpooch]

C(13,2)xC(4,2)xC(4,2)x(52-2x4)= 123552; divide by C(52,5)
to get 123552/2598960 or about 0.047539016.

[NickNick]

I got KKKK6 before the draw to double up late in a tourney! Think I got a 7 when I drew for the flush...