Settle this Poker Theory / Sklansky bucks debate

[jono]

No player has greater or less EV than the other player. BBs are inconsequential NoTurns. I posted the math in MSNL.

[PantsOnFire]

For NL100 the EV for player A is 20% of the money wagered - the cost of his bets. 2000*.20 - 1000 = -$600. For NL1,000 the EV for player A is 80% of the money wagered - the cost of his bets. 2000*.80 - 1000 = +$600.

1. Total EV for Player A is: neutral

For NL100 the EV for player B is 80% of the money wagered - the cost of his bets. 2000*.80 - 1000 = +$600. For NL1,000 the EV for player B is 20% of the money wagered - the cost of his bets. 2000*.20 - 1000 = -$600.

2. Total EV for Player A is: neutral

The results indicate that both players ran neutral for this trial.

I kinda did this in my head at first and then worked it out thinking there was trick here somewhere. I can't find anything of note, are you sure this is your question?

[Galwegian]

I'm presuming that each all in for 100BB (that seems to be implied in your post)

If we don't know the results of each hand, then the ev of both players over this seqeunce of hands is 0.

[eMbAh]

[ QUOTE ]
I'm presuming that each all in for 100BB (that seems to be implied in your post)

If we don't know the results of each hand, then the ev of both players over this seqeunce of hands is 0.

[/ QUOTE ]

?

[wtfsvi]

this thread is wow

of course each player's EV is $0