beat: douchey math teacher doesnt understand math (mspaint fun inside)

[Triptanes]

no @ ur second graph

[Max Raker]

your second graph makes no sense to me. The other two are reasonable. I would mark either one correct if I was the prof.

[kevin017]

the professor's answer can't possibly be right. limesparks picture above was the best answer. Boom's first answer also works. 2nd answer doesn't.

[IlliniLou]

[ QUOTE ]
PV = nRT
P = nRT/V

nRT are constant so P is inversely related to V. Linearly related.

So as V gets bigger, P gets smaller and vice versa. They gave away the answer in the first sentence. Except for the linear part. WTF?

[/ QUOTE ]
DBZ talkin about math is so hawt- also ... i have a headache from tryin to comprehend your professors graph

[ebepse]

does the axis necessarily mean zero?

for the first one i guess your explanation is fine but ur not including part so i could see why he could mark it wrong. sometimes nitty [censored] like that is important.

imo open circles on the axes would be best.

yeah and 2nd is ldo wrong

[DoGGz]

[ QUOTE ]
does the axis necessarily mean zero?

for the first one i guess your explanation is fine but ur not including part so i could see why he could mark it wrong. sometimes nitty [censored] like that is important.

imo open circles on the axes would be best.

yeah and 2nd is ldo wrong

[/ QUOTE ]

Axis doesn't have to be 0, but without denoting it otherwise then yes it should be 0.

Boost > both you and teacher fail at math.

[klownage]

lolololol @ graph 2

[pa3lsvt]

[edit]Oh I grunched. Second graph is for crackheads, but 'A for effort' since the earlier (CORRECT) answer was marked off. Please elaborate prof's justification fro his being right, and your graph #1 being wrong.
PS Asymptotes make earlier graph more accurate than mine, but that describes actual relationship between P and V, not the Ideal Gas Law model.[/edit]

grunch:

Geebus, this is simple Ideal Gas Law (PV=nRT). The term nRT remains constant. So as P increases, V decreases; as P decreases, V increases. Inverse proportional relationship. P EQUALS K TIMES INVERSE V.

[Limesparks]

[ QUOTE ]
[edit]Oh I grunched. Second graph is for crackheads, but 'A for effort' since the earlier (CORRECT) answer was marked off. Please elaborate prof's justification fro his being right, and your graph #1 being wrong.
PS Asymptotes make earlier graph more accurate than mine, but that describes actual relationship between P and V, not the Ideal Gas Law model.[/edit]

grunch:

Geebus, this is simple Ideal Gas Law (PV=nRT). The term nRT remains constant. So as P increases, V decreases; as P decreases, V increases. Inverse proportional relationship. P EQUALS K TIMES INVERSE V.



[/ QUOTE ]

dude, if nRT is a constant k, then V = k/P. graph this on ur calculator its not a straight line i swear

make ur graph log V vs. log P and then we got a deal

[ebepse]

limesparks is right imo