Beat I am mathematically challenged today

[Kimbell175113]

holy crap, I made a mistake and it's all messed up. I hate life.

[derosnec]

sorry, forgot to say, that one condition is that none of the variables can be negative

[derosnec]

[ QUOTE ]
edit: thanks for this thread. now i'm def going back to school

[/ QUOTE ]

seriously. i am doing something and one small part involves system of equations. and i'm like "oh [censored], how do i do this stuff again"

[danzasmack]

"none of the variables can be negative"

Does that mean X > 0 or the coefficient > 0?

[U6C84]

[ QUOTE ]
2 equations, 4 unknowns. do i just substitute? when doing so things get really cumbersome.

$25 transfer on stars (when i get home tonight) if someone wants to tackle it (probably easy to you geeks). first person gets $$.

6w + 6x + 4y + 2z = 5

w + x + y + z = 1

[/ QUOTE ]

w = 0.25 x = 0.25 y = 0.5 z = 0

6(.25) + 6(.25) + 4(.5) + 0 = 5
1.5 + 1.5 + 2 = 5

0.25 + 0.25 + 0.5 + 0 = 1

If you throw in that 3rd equation..this doesn't work

[alphatmw]

y = 0.5 -2z
x = 0.5 + -1y

you need 1 more equation

[rwesty]

w=.25, x=.5, y=0, z=.25

I win.

[Limesparks]

[ QUOTE ]
w=.25, x=.5, y=0, z=.25

I win.

[/ QUOTE ]

Damn. Just beat me.

Matrices FTW

[Kimbell175113]

Yep.

[LeatherFace]

[ QUOTE ]
[ QUOTE ]
2 equations, 4 unknowns. do i just substitute? when doing so things get really cumbersome.

$25 transfer on stars (when i get home tonight) if someone wants to tackle it (probably easy to you geeks). first person gets $$.

6w + 6x + 4y + 2z = 5

w + x + y + z = 1

[/ QUOTE ]

w = 0.25 x = 0.25 y = 0.5 z = 0

6(.25) + 6(.25) + 4(.5) + 0 = 5
1.5 + 1.5 + 2 = 5

0.25 + 0.25 + 0.5 + 0 = 1

If you throw in that 3rd equation..this doesn't work

[/ QUOTE ]

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