#1
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Very basic question here
If a player bets 40$, and I raise by 40$ (to 80$), is the player after me forced to raise by another 40$ (for a total of 120$) or by 80$ (for a total of 160$)?
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#2
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Re: Very basic question here
I mean, ofcourse, if he chooses to re-raise. Sorry for not clarifying.
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#3
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Re: Very basic question here
He has to raise at least the same as the last raise, which was $40. He can still move all-in with less than that $40 though [img]/images/graemlins/smile.gif[/img]
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#4
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Re: Very basic question here
Perfect! Thank you Nightlight [img]/images/graemlins/smile.gif[/img]
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#5
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Re: Very basic question here
Each bet must be 2x the bet before it. So, he must raise by $80.
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#6
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Re: Very basic question here
Umm... ok. That's 2 different answers. Who's right?
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#7
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Re: Very basic question here
[ QUOTE ]
Each bet must be 2x the bet before it. So, he must raise by $80. [/ QUOTE ]Not in any game I have ever seen or played in. |
#8
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Re: Very basic question here
[ QUOTE ]
Each bet must be 2x the bet before it. So, he must raise by $80. [/ QUOTE ] that is a complete wrong answer. no idea what weird houserules you play with. |
#9
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Re: Very basic question here
Ok I think I get it. The minimum raise in any round is always either the BB or the last raise amount that round. In the next round, it resets back to the BB, right?
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#10
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Re: Very basic question here
Yeh that's right. Just think of the BB as the initial bet, so you either have to call, or raise it by at least as much, or fold.
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