Break even points

[Red_Diamond]

I was reading a chapter from a Hilger book. He mentions a case where there is $24.75 in the pot, and your opponent has 4-1 odds of drawing out on you. To calc the breakeven point for your bet he shows the following calc:

(24.75 + x) / x = 4.1
24.75 = 3.1x
x = 8.98

I have tried to make sense of this, and while it sorta-kinda does at a quick glance, a calculation (at least when I do them) just doesn't add up accordingly. I am tired and maybe missing the obvious, but can someone verify what the hell I am missing here?

BTW, this is from p. 145, Odds & Probabilities

[BruceZ]

[ QUOTE ]
I was reading a chapter from a Hilger book. He mentions a case where there is $24.75 in the pot, and your opponent has 4-1 odds of drawing out on you. To calc the breakeven point for your bet he shows the following calc:

(24.75 + x) / x = 4.1
24.75 = 3.1x
x = 8.98

I have tried to make sense of this, and while it sorta-kinda does at a quick glance, a calculation (at least when I do them) just doesn't add up accordingly. I am tired and maybe missing the obvious, but can someone verify what the hell I am missing here?

BTW, this is from p. 145, Odds & Probabilities

[/ QUOTE ]

The opponent must call a bet of size x in order to win a pot of size 24.75+x, so his pot odds are (24.75+x) to x or (24.75+x)/x to 1, so to break even, this must be equal to 4.1-to-1 if the odds against making his hand are 4.1-to-1. This arithmetic is wrong though since x = 7.98.

[Red_Diamond]

Ok thanks for the clarification Bruce. Must have been a typo on his part.