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#1
10-23-2007, 05:03 PM
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the more likely perfect season?
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#3
10-23-2007, 05:37 PM
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Re: the more likely perfect season?
[ QUOTE ]
How could both pairs have a better chance at a perfect season? [/ QUOTE ] "or" BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither.
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#4
10-23-2007, 05:41 PM
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Re: the more likely perfect season?
[ QUOTE ]
[ QUOTE ] How could both pairs have a better chance at a perfect season? [/ QUOTE ] "or" BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither. [/ QUOTE ] i don't see how it's retarded. either one team from both groups will finish perfect, or all 4 teams will finish imperfect. unlikely? yes, very. retarded? [img]/images/graemlins/frown.gif[/img]
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#5
10-23-2007, 05:45 PM
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Re: the more likely perfect season?
[ QUOTE ]
[ QUOTE ] [ QUOTE ] How could both pairs have a better chance at a perfect season? [/ QUOTE ] "or" BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither. [/ QUOTE ] i don't see how it's retarded. either one team from both groups will finish perfect, or all 4 teams will finish imperfect. unlikely? yes, very. retarded? [img]/images/graemlins/frown.gif[/img] [/ QUOTE ] Except you asked which one is more likely. They can't both be more likely ducy?
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#6
10-23-2007, 05:50 PM
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Re: the more likely perfect season?
[ QUOTE ]
[ QUOTE ] [ QUOTE ] [ QUOTE ] How could both pairs have a better chance at a perfect season? [/ QUOTE ] "or" BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither. [/ QUOTE ] i don't see how it's retarded. either one team from both groups will finish perfect, or all 4 teams will finish imperfect. unlikely? yes, very. retarded? [img]/images/graemlins/frown.gif[/img] [/ QUOTE ] Except you asked which one is more likely. They can't both be more likely ducy? [/ QUOTE ] well, st. louis doesn't play NE, so if NE wins out and STL loses out, then voila
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#7
10-24-2007, 05:17 AM
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Re: the more likely perfect season?
[ QUOTE ]
[ QUOTE ] [ QUOTE ] [ QUOTE ] How could both pairs have a better chance at a perfect season? [/ QUOTE ] "or" BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither. [/ QUOTE ] i don't see how it's retarded. either one team from both groups will finish perfect, or all 4 teams will finish imperfect. unlikely? yes, very. retarded? [img]/images/graemlins/frown.gif[/img] [/ QUOTE ] Except you asked which one is more likely. They can't both be more likely ducy? [/ QUOTE ] I believe that he is asking which is most likely out of those 4 choices. The answer is "neither" by a country mile.
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#8
10-23-2007, 05:46 PM
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Re: the more likely perfect season?
There is no way that the odds of the Pats and Colts losing a game (they play each other, to boot) and the Rams and Dolphins winning a game is less than any 4 of them winning or losing out.
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#9
10-24-2007, 04:22 AM
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Re: the more likely perfect season?
You guys do know that for neither to be the correct answer the chances of both the pairs having a perfect season have to be exactly equal. The question is which result is MORE likely not whether it is likely that neither will happen.. Granted the poll is so retarded you have to smart to understand it, but c'mon get with the program.
The only way for neither pair to be more likely is for them to be equivalently likely and as I and others have said there is no way for them both to be more likely than each other. So, anyone answering both or neither as anything but a joke doesn't understand the question as presented. It's hard to blame you though when the presenter doesn't know what he is asking.
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