Beat I am mathematically challenged today

[danzasmack]

3 equations, 4 unknowns = infinite solution

the solution will be a curve so it's the portion of the graph where they are all >= 0. If that point is relative max then that is a solution. Is it?

Is that right, what I said? I know you can't just use matrices and assume the solution is correct.

[U6C84]

Had to edit..used the wrong equation



For all 3 equations on top, For 2 equations on bottom

Stars SN: U6C84

[danzasmack]

you're all wrong!

[derosnec]

it turns out that one of the conditions is that they must be greater than zero. i should have said that earlier. if people are sick of this (i know i am), i can send the $$ to whoever answered it first. just pm me.

mods: please change my title to "Negative IQ". thanks.

[U6C84]

Here it is with all Variables > 0

[pureCra2z]

what kind of class maeks you do this tedious work with all these unreasonable conditions.

[SWINGMYTOOL]

danzasmack is right. Four unknowns + three linear questions = infinitely many solutions.

Also, don't waste brains and ink and Excel on this, kids. There are websites for stuff like this.

Pick anything you want for z, and the values of w, x, and y are:
w = -(2*z-1)/2
x = 2*z
y = -(4*z-1)/2
z = z

Since you said they all have to be greater than zero, pick any z so that 0 < z < .25

[RedJoker]

(1/4)<w<(1/2)
0<x<(1/2)
0<y<(1/2)
0<z<(1/4)

[RedJoker]

[ QUOTE ]
the solution will be a curve so it's the portion of the graph where they are all >= 0.

[/ QUOTE ]

LOL fourdimensionalcurveaments

[RedJoker]

[ QUOTE ]
(1/4)<w<(1/2)
0<x<(1/2)
0<y<(1/2)
0<z<(1/4)

[/ QUOTE ]

The working out:

6w + 6x + 4y + 2z = 5 ............ <font color="red"> Eq 1 </font>
w + x + y + z = 1 ................. <font color="red"> Eq 2 </font>
12w + 8x + 8y + 12z = 10 ...... <font color="red"> Eq 3 </font>

<font color="red"> Eq 1 </font> - 6( <font color="red"> Eq 2 </font>)

-&gt; y = (1 - 4z)/2 ............... <font color="blue"> Eq 4 </font>

<font color="red"> Eq 3 </font> - 2(<font color="red"> Eq 1 </font>)

-&gt; x = 2z ......................... <font color="blue"> Eq 5 </font>

<font color="red"> Eq 3 </font> - 8(<font color="red"> Eq 2 </font>)

-&gt; w = (1 - 2z)/2 ............... <font color="blue"> Eq 6 </font>

From <font color="blue"> Eq 4 </font>:

y &gt; 0
y = (1 - 4z)/2

(1 - 4z)/2 &gt; 0

z &lt; (1/4).................... <font color="green"> Soln 1 </font>

From <font color="blue"> Eq 5 </font>:

x = 2z
z &lt; (1/4)

x &lt; (1/2)............ <font color="green"> Soln 2 </font>

From <font color="blue"> Eq 4 </font>

y = (1 - 4z)/2
z &gt; 0

y &lt; (1 - 4[0])/2

y &lt; (1/2) ....................... <font color="green"> Soln 3 </font>

From <font color="blue"> Eq 6 </font>:

w = (1 - 2z)/2
z &lt; (1/4)

w &gt; (1 - 2[1/4])/2

w &gt; (1/4)

z &gt; 0

w &lt; (1 - 2[0])/2

w &lt; (1/2)

(1/4) &lt; w &lt; (1/2) ........... <font color="green"> Soln 4 </font>