What is "Nash equilibrium" as it relates to NLHE?

[dj_mercury]

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Thanks for the responses. [img]/images/graemlins/smile.gif[/img] Very heavy stuff, though. lol

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The classic exemple to explain the concept is the Prisoner Dilemma.

[rufus]

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I'm not convinced this 1949 proof is valid for dynamic multi-street poker games. Every example shown is a one street static payoff game. In poker there is more than one street. Also the payoffs change with every street in an unpredictable manner.

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The number of possible situations is finite. So, although you typically make decisions during the game, it's (theoretically) possible to make all of the decisions beforehand. So, we can think of each possible list of choices as a pure strategy. This geometrically explodes the number of pure strategies, but we don't care as long as there's only a finite number.

[Paxinor]

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I'm not convinced this 1949 proof is valid for dynamic multi-street poker games. Every example shown is a one street static payoff game. In poker there is more than one street. Also the payoffs change with every street in an unpredictable manner.


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it also exists for poker. "a street" is somewhat missleading intuition. basicly you cannot avoid EV if you play every flop optimal so it doesnt really matter if you raise a hand with a certain equity or just call and play each flop acordingly.

the games listed are just simple example. if you try to calculate nash equilibrium for a cardagme like poker, its not gonna fit on a couple of pages "as an example"

basicly every n-player zerosum game has a nash equilibrium, if everbody maximizes his +EV...

doesn't matter if dynamic or static, multistreet or singlestreet ...