what are the odds...

[jupiterpig]

What are the odds of getting the same 2 hole cards (suits and all) in back to back hands at the same table? I have had this happen 2 times within 10 days...once with AA and once with AK...

Also what are the odds of the same hand at 2 tables with identical flops (except suits)??

sorry if this is the wrong place for this...

[Piemaster]

Every time you are dealt a hand, there is a 1 in 1326 chance that it will be the same hand (suits and all) as the last one you were dealt on that table.

In other words, if you play a lot of hands, it will happen quite regularly.

[ispiked]

Can you go over how you calculated that, Piemaster?

[jay_shark]

Well if you played 2 hands , then the probability the second hand is the same as the first is 1/52C2=1/1326 .

52c2 = 52*51/2 =1326 .

Here's how it works .

For the first card , you have 52 choices . Once you have 52 choices for your first card , you have 51 choices for your second card . However ,everytime you have a card combination like 2c4h you've also included 4h2c so to avoid this over-counting , you must divide 52*51 by 2 .

[jay_shark]

A better question to ask , is what's the probability I get dealt the same 2 hole cards in x amount of deals . Over a lifetime , if you've played poker long enough , you'll probably see everything happen .In 10 deals , the probability you get dealt the same hole cards back to back is :

9*1/52c2 - 9c2*1/(52c2)^2 +9c3*1/(52c2)^3 -...9c9*1/(52c2)^9 which is about 9/52c2 since the probabilities you add and subtract are negligible with only 10 deals .