Two Plus Two Newer Archives  

Go Back   Two Plus Two Newer Archives > General Gambling > Probability
FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
  #11  
Old 10-28-2007, 06:40 PM
Rowem Rowem is offline
Junior Member
 
Join Date: May 2007
Posts: 29
Default Re: Variance question

Just out of interest...what is the probability of being 10 standard deviations from the mean?
Reply With Quote
  #12  
Old 10-28-2007, 07:45 PM
DrVanNostrin DrVanNostrin is offline
Senior Member
 
Join Date: Sep 2005
Location: throwing my cards at the dealer
Posts: 656
Default Re: Variance question

< 10^-29
Reply With Quote
  #13  
Old 10-28-2007, 09:32 PM
AaronBrown AaronBrown is offline
Senior Member
 
Join Date: May 2005
Location: New York
Posts: 2,260
Default Re: Variance question

Under a Normal distribution, you will be more than 10 standard deviations from the mean with probability 1.5 x 10^-23. Since this isn't going to happen, if you think it did, either (a) it isn't a Normal distribution, (b) you computed the mean or standard deviation wrong, or (c) you're psychotic (the chances of being too insane to know you're insane is about 0.001, so any time you claim a probability is smaller than this, you should consider the chance that you're crazy).

No more than 1/100 of the observations can lie beyond 10 standard deviations from the mean, regardless of the distribution. Suppose you have a distribution with 0.99 chance of 0, 0.005 chance of -10 and 0.005 chance of +10. The mean is zero, and the standard deviation is 1. 0.01 of the observations are 10 standard deviations from the mean.
Reply With Quote
  #14  
Old 10-29-2007, 12:48 AM
DrVanNostrin DrVanNostrin is offline
Senior Member
 
Join Date: Sep 2005
Location: throwing my cards at the dealer
Posts: 656
Default Re: Variance question

[ QUOTE ]
Under a Normal distribution, you will be more than 10 standard deviations from the mean with probability 1.5 x 10^-23.

[/ QUOTE ]
Where did you get this?

=normdist(10,0,1,true) in Excel just gave me 1.000.. (a total of 30 0's). Is Excel unreliable for this many decimal places?
Reply With Quote
  #15  
Old 11-01-2007, 02:59 PM
TNixon TNixon is offline
Senior Member
 
Join Date: Apr 2007
Posts: 616
Default Re: Variance question

[ QUOTE ]

Where did you get this?

=normdist(10,0,1,true) in Excel just gave me 1.000.. (a total of 30 0's). Is Excel unreliable for this many decimal places?

[/ QUOTE ]

If excel's normdist function can be used to determine the how likely you are to be within X std deviations, then shouldn't

=normdist(1,0,1,true)

give .68?

It gives me .8413.
Reply With Quote
  #16  
Old 11-01-2007, 04:45 PM
TNixon TNixon is offline
Senior Member
 
Join Date: Apr 2007
Posts: 616
Default Re: Variance question

Answered the excel question for myself, after doing a bit more searching.

Excel's normdist function gives the portion that is less than the argument.

So normdist(1,0,1,true) isn't the distribution from -1 to 1, it's the distrubution from -infinity to 1.

Which would certainly explain the 7 decimal place difference.
Reply With Quote
  #17  
Old 11-07-2007, 11:16 PM
Troll_Inc Troll_Inc is offline
Senior Member
 
Join Date: Mar 2006
Location: FGHIJKLM STUVWXYZ
Posts: 2,566
Default Re: Variance question

[ QUOTE ]
Normal distibutions are quite common because of the Central Limit Theorem. Even if the results of your individual hands do not follow a normal distibution, the results of your 100 hand sessions will.

[/ QUOTE ]

How many of these 100 count hand sessions are needed before your results become normally distributed?
Reply With Quote
Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 09:41 PM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.