#1
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Question about probability in stud
I am trying to calculate the probability of having a particular hand by 5th street in 7 card stud. If i know the probability of having it on 4th and the probability on having it on 5th (after 1 card each time) how do you combine the two to find the probability of getting that hand by 5th street. For example with 8 players, starting with a pair the probability of having 3 of a kind on 4th is 1:21 (42 cards /2). How does one calculate the probability over more than 1 street?
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#2
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Re: Question about probability in stud
There are various ways of doing so.
Say you are dealt a pair of 5's. The probability of getting trips by 5th street is the sum: P(getting trips on 4th street) + P(getting trips on 5th street) given you did not get trips on 4th street In the example of being dealt say 55A, the probability of trips by 5th street: 2/49 + 47/49 * 2/48 Probability by 6th street: 2/49 + 47/49 * 2/48 + 47/49 * 46/48 * 2/47 You are adding up the all possible cases of reaching trips. This method gets cumbersome and there are easier methods if you're familiar with basic combinatorics. |
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