#1
|
|||
|
|||
Quadratic Equation
I'm taking a class and cannot come up with an answer to this question...any help would be appreciated...
Come up with a real life situation modeled by (X-3)(X-4) = 0. Help!! |
#2
|
|||
|
|||
Re: Quadratic Equation
Hint 1: Try using basic physics equations.
Hint 2: x^2 - 7x + 12 = 0 |
#3
|
|||
|
|||
Re: Quadratic Equation
Replace the x with a t .
V(t) = (t-3)(t-4) where t= time . V(t) is the velocity function with respect to time . If you're interested in time t for when the velocity of some moving object is 0 then you find the roots . The displacement function is S(t) such that S'(t)=V(t) . It's obvious that between t=3 and t=4 there is negative velocity and for t>4 , the velocity becomes positive . |
#4
|
|||
|
|||
Re: Quadratic Equation
You could model a spring-mass damper system. Assuming the damping coefficient was related to the mass velocity; and there was no other forces acting on the mass. Weight can be ignored if system starts from equilibrium.
From F = ma kx + bx' = mx" The characteristic eqn would become x^2 - 7x + 12 = 0 mass m = 1 damping coefficient b = -7 spring constant k = 12 |
#5
|
|||
|
|||
Re: Quadratic Equation
If you want a non-physics application... consider frames for different sizes of pictures, with the photo placed inside a matte that is 2" wide above and below the picture and 1 1/2" wide to either side of it... (X-3)(X-4) is the area of the largest matted picture that can be displayed in an X by X frame.
|
#6
|
|||
|
|||
Re: Quadratic Equation
well since the equation forms a parabolic graph, you can do something like a person is standing on top of a 12 foot roof, he throws a ball upwards, this equation would model this well since the equation of the flight of the ball would be parabolic and this would start at this height. Hope this helps
|
#7
|
|||
|
|||
Re: Quadratic Equation
As expected...people on this forum are intelligent and fast and courteous...thanks for the responses...
|
|
|