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View Poll Results: Auburn 9-1
1 0 0%
2 0 0%
3 0 0%
4 12 27.91%
5 13 30.23%
6 7 16.28%
7 4 9.30%
8 3 6.98%
9 1 2.33%
10 3 6.98%
Voters: 43. You may not vote on this poll

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  #1  
Old 10-23-2007, 05:03 PM
BowToYourSensei BowToYourSensei is offline
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Default the more likely perfect season?

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  #2  
Old 10-23-2007, 05:11 PM
Bork Bork is offline
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Default Re: the more likely perfect season?

How could both pairs have a better chance at a perfect season?
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  #3  
Old 10-23-2007, 05:37 PM
kyro kyro is offline
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Default Re: the more likely perfect season?

[ QUOTE ]
How could both pairs have a better chance at a perfect season?

[/ QUOTE ]

"or"

BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither.
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  #4  
Old 10-23-2007, 05:41 PM
BowToYourSensei BowToYourSensei is offline
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Default Re: the more likely perfect season?

[ QUOTE ]
[ QUOTE ]
How could both pairs have a better chance at a perfect season?

[/ QUOTE ]

"or"

BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither.

[/ QUOTE ]

i don't see how it's retarded. either one team from both groups will finish perfect, or all 4 teams will finish imperfect. unlikely? yes, very. retarded? [img]/images/graemlins/frown.gif[/img]
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  #5  
Old 10-23-2007, 05:45 PM
Bremen Bremen is offline
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Default Re: the more likely perfect season?

[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
How could both pairs have a better chance at a perfect season?

[/ QUOTE ]

"or"

BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither.

[/ QUOTE ]

i don't see how it's retarded. either one team from both groups will finish perfect, or all 4 teams will finish imperfect. unlikely? yes, very. retarded? [img]/images/graemlins/frown.gif[/img]

[/ QUOTE ]
Except you asked which one is more likely. They can't both be more likely ducy?
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  #6  
Old 10-23-2007, 05:46 PM
kyro kyro is offline
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Default Re: the more likely perfect season?

There is no way that the odds of the Pats and Colts losing a game (they play each other, to boot) and the Rams and Dolphins winning a game is less than any 4 of them winning or losing out.
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  #7  
Old 10-23-2007, 05:50 PM
BowToYourSensei BowToYourSensei is offline
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Default Re: the more likely perfect season?

[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
[ QUOTE ]
How could both pairs have a better chance at a perfect season?

[/ QUOTE ]

"or"

BTYS, if you're gonna make a poll like this, putting neither and both as choices is retarded. Of course the answer is neither.

[/ QUOTE ]

i don't see how it's retarded. either one team from both groups will finish perfect, or all 4 teams will finish imperfect. unlikely? yes, very. retarded? [img]/images/graemlins/frown.gif[/img]

[/ QUOTE ]
Except you asked which one is more likely. They can't both be more likely ducy?

[/ QUOTE ]

well, st. louis doesn't play NE, so if NE wins out and STL loses out, then voila
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  #8  
Old 10-23-2007, 05:56 PM
Dudd Dudd is offline
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Default Re: the more likely perfect season?

Yes, but a percent multiplied by a percent is a smaller percent, ducy?
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  #9  
Old 10-23-2007, 05:57 PM
BowToYourSensei BowToYourSensei is offline
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Default Re: the more likely perfect season?

guys, i'm really stoned, please don't make me try to use statistical reasoning
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  #10  
Old 10-23-2007, 06:02 PM
Case Closed Case Closed is offline
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Default Re: the more likely perfect season?

I think the Dolphins have the best shot at the perfect season followed by the rams then the colts(homer) then the Patriots.

The colts/pats don't really have much of a shot because they will wrap up playoffs and it will increase the chances of them losing a late game while the Dolphins and Rams will suck no matter time of year it is.
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