Two Plus Two Newer Archives  

Go Back   Two Plus Two Newer Archives > General Gambling > Sports Betting
FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
  #1  
Old 08-27-2007, 10:51 AM
UMTerp UMTerp is offline
Senior Member
 
Join Date: Oct 2003
Location: Columbia, MD
Posts: 2,965
Default NFL Wins total Question

Hopefully I can phrase this reasonably... what is it generally accepted that the "right odds" are for "buying a win" in a season-long win total bet in the NFL?

Obviously, going from 7 to 8 wins is different from 14 to 15 wins, but assume a middle-of-the pack team.

Like if the Redskins are even money to win o/u 7.5, what should the odds be for o/u 8.5? -180 for under? Longer/shorter than that? How about half a win for a middle-of-the-pack team?

Thanks.
Reply With Quote
  #2  
Old 08-27-2007, 11:42 AM
ImStillBen ImStillBen is offline
Senior Member
 
Join Date: Feb 2007
Posts: 233
Default Re: NFL Wins total Question

-223.18
Reply With Quote
  #3  
Old 08-27-2007, 08:10 PM
bevo_stevo bevo_stevo is offline
Member
 
Join Date: Aug 2007
Location: Texas
Posts: 39
Default Re: NFL Wins total Question

Bens correct, but the answer probably wasn't very helpful (par for the course there).

You should probably get out Excel (or OpenOffice if you're an anarchist) and play around with the BINOMDIST function. Create a column numbered 0..16. Use 7.5/16 = 0.46875 for the probability, 16 for the number of trials - the season length, and reference the corresponding cell in the 0..16 column to determine how likely it is to win a given number of games.

This really isn't all that difficult once you get a little intuition about how it works. Good luck.
Reply With Quote
  #4  
Old 08-27-2007, 09:27 PM
Thremp Thremp is offline
Senior Member
 
Join Date: Nov 2005
Location: Free Kyleb
Posts: 10,163
Default Re: NFL Wins total Question

[ QUOTE ]
Bens correct, but the answer probably wasn't very helpful (par for the course there).

You should probably get out Excel (or OpenOffice if you're an anarchist) and play around with the BINOMDIST function. Create a column numbered 0..16. Use 7.5/16 = 0.46875 for the probability, 16 for the number of trials - the season length, and reference the corresponding cell in the 0..16 column to determine how likely it is to win a given number of games.

This really isn't all that difficult once you get a little intuition about how it works. Good luck.

[/ QUOTE ]

Handing out your rice bowl is -EV.
Reply With Quote
  #5  
Old 08-27-2007, 11:01 PM
bevo_stevo bevo_stevo is offline
Member
 
Join Date: Aug 2007
Location: Texas
Posts: 39
Default Re: NFL Wins total Question

[ QUOTE ]

Handing out your rice bowl is -EV.

[/ QUOTE ]

I never would have guessed a 1st semester Statistics course would be the Holy Grail of sports betting. This information has been discussed plenty of other places, even in 2+2 magazine itself. So if you think this sort of computation is difficult, or "sharp", you're just plain wrong.
Reply With Quote
Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 09:09 AM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.