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#1
09-08-2007, 07:24 PM
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ned startegy for between the sheets
I didn't know where to put this(it could also be in home poker and i'll probably post there). In my regular home game we play between the sheets. It a game where two cards are flipped and and you bet any amount that is in the pot that the next card will be in between the two.
Normally the game can get big. We use dollar chips and the pot normally grows to 300-400 dollars because of double burns. Where lets say a 2 and k comes up and you pot it with 100 in the pot. If a 2 or k come up you owe 200. So is there anywhere i can find a strategy to this game as far as betting x amount with x amount in the pot with x outs. 
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#2
09-08-2007, 09:27 PM
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Re: ned startegy for between the sheets
Assuming that we're not counting cards to know what's in the deck and adjusting accordingly...
If there are more than six ranks in between, bet the max, since there are more winners than losers in the deck and any bet is +EV. If there are six or fewer ranks in between, bet the min., because any bet is -EV.
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#3
09-08-2007, 10:37 PM
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Re: ned startegy for between the sheets
[ QUOTE ]
Assuming that we're not counting cards to know what's in the deck and adjusting accordingly... If there are more than six ranks in between, bet the max, since there are more winners than losers in the deck and any bet is +EV. If there are six or fewer ranks in between, bet the min., because any bet is -EV. [/ QUOTE ] ??? There are a total of 13 ranks -- but there are also 2 rails. If you hit outside the rails, you lose. If you hit the rail, you pay double (lose double). If you use > six ranks, then you have (using 7): 28 ways to win 1 6 ways to lose 2 16 ways to lose 1 +28 -12 -16 = 0 That doesn't look like a winning strategy to me.
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#4
09-09-2007, 04:03 PM
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Re: ned startegy for between the sheets
Oh, I missed that part. Sorry 'bout that. He's right. Seven is 0EV, so probability-wise, the bet size is irrelevant.
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#5
09-09-2007, 10:50 PM
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Re: ned startegy for between the sheets
[ QUOTE ]
Oh, I missed that part. Sorry 'bout that. He's right. Seven is 0EV, so probability-wise, the bet size is irrelevant. [/ QUOTE ] Analyzing probability, the bet size is always irrelevant. Because the expectation is zero -- the EV will always be zero.
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