quick 6max maths question

Pokerdemic · #1 09-26-2007, 11:15 PM

If I am dealt a random hand that is not paired, what is the probability that at least one of the other five players was dealt a pair? Anyone know how to figure this out?

jay_shark · #2 09-26-2007, 11:32 PM

The approximate probability is

1- [(1225-78)/1225]^5 ~ 28.03%

Read a similar post in the probability forum , titled "full house and quads" for an explanation .

Pokerdemic · #3 09-27-2007, 03:06 AM

my bad. completely forgot probability forum existed. thanks anyway

shark steak · #4 09-27-2007, 06:32 AM

sorry, new to the site, how can I find the "full house and quads" forum?
thanks

jay_shark · #5 09-27-2007, 08:47 AM

Look on the left hand side and click under "General Gambling" . You should be able to see the probability section right underneath it .

shark steak · #6 09-27-2007, 05:08 PM

Found it, thank you jay