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Hey dorks. A problem for you.
My pop once worked this out for me. Its a problem that he came up with after the classic "put the damn toilet seat down" argument with Mom.
The question is, which requires more work: A. The man always puts the toilet seat down when he's done. B. The man never changes the position of the toilet seat when he's done. Some assumptions: - The seat moving up and down both require the same amount of work, and should obviously be considered as 1 unit of work per movement. - The woman must always have the seat down. - The man must always have it down for the deuce, and up for peeing. - There is exactly 1 man and 1 woman to the toilet seat. - For the sake of argument, each pees 4 times a day, and drops off the kids 1 time per day. - The order at which they use the toilet is completely random. The man could go all 5 times, then the woman the next 5, or any combination throughout the day. If you want to change some of the variables to make the problem more interesting (I don't think its terribly difficult) feel free. I dunno if this is that interesting but alot of you guys flipped out over those physics problem. Maybe this will spark some interesting math stuff. Also, I'm a dork. -Jihad |
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