Two Plus Two Newer Archives  

Go Back   Two Plus Two Newer Archives > Other Topics > Science, Math, and Philosophy
FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
  #1  
Old 03-30-2007, 12:44 AM
Siegmund Siegmund is offline
Senior Member
 
Join Date: Feb 2005
Posts: 1,850
Default A puzzle for jay_shark et al.

One of my personal favourites - actually, one of very few bits of mathematical trivia I discovered for myself and never subsequently ran across in a book anywhere.

Let X be a point selected at random from the standard middle-thirds-deleted Cantor Set on [0,1]. What is Var(X)?
Reply With Quote
  #2  
Old 03-30-2007, 01:20 AM
jason1990 jason1990 is offline
Senior Member
 
Join Date: Sep 2004
Posts: 932
Default Re: A puzzle for jay_shark et al.

<font color="white">I would construct a random element from the Cantor set as follows. Let X_n be an iid sequence with P(X_n = 0) = P(X_n = 1) = 0.5, and define the random element as

X = \sum_{n=1}^\infty 2X_n/3^n.

We then have

Var(2X_n/3^n) = (4/9^n)Var(X_n) = 1/9^n.

Since the summands are independent, the variances add, giving

Var(X) = \sum_{n=1}^\infty 1/9^n = 1/8.

(The Dominated Convergence Theorem justifies adding the variances all the way to infinity.)</font>
Reply With Quote
  #3  
Old 03-30-2007, 01:22 AM
bxb bxb is offline
Senior Member
 
Join Date: Apr 2006
Posts: 347
Default Re: A puzzle for jay_shark et al.

I got 1/8.
Reply With Quote
  #4  
Old 03-30-2007, 03:16 PM
Siegmund Siegmund is offline
Senior Member
 
Join Date: Feb 2005
Posts: 1,850
Default Re: A puzzle for jay_shark et al.

You're right. Both of you, that is. Too easy
Reply With Quote
Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 12:58 AM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.