#1
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A puzzle for jay_shark et al.
One of my personal favourites - actually, one of very few bits of mathematical trivia I discovered for myself and never subsequently ran across in a book anywhere.
Let X be a point selected at random from the standard middle-thirds-deleted Cantor Set on [0,1]. What is Var(X)? |
#2
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Re: A puzzle for jay_shark et al.
<font color="white">I would construct a random element from the Cantor set as follows. Let X_n be an iid sequence with P(X_n = 0) = P(X_n = 1) = 0.5, and define the random element as
X = \sum_{n=1}^\infty 2X_n/3^n. We then have Var(2X_n/3^n) = (4/9^n)Var(X_n) = 1/9^n. Since the summands are independent, the variances add, giving Var(X) = \sum_{n=1}^\infty 1/9^n = 1/8. (The Dominated Convergence Theorem justifies adding the variances all the way to infinity.)</font> |
#3
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Re: A puzzle for jay_shark et al.
I got 1/8.
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#4
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Re: A puzzle for jay_shark et al.
You're right. Both of you, that is. Too easy
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