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#1
10-31-2007, 11:27 AM
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Re: Badugi Dilemma
[ QUOTE ]
[ QUOTE ] He has 10 outs to a badugi while you only have 9. (no Q!) [/ QUOTE ] I'm not sure how deeply we want to get into this, but the above is only true if they are drawing to the same suit; otherwise it should be 9 and 8. Correct? (Even if they draw to the same suit, the queen is gone, so it might be 9 and 9. hmmm...) [/ QUOTE ] If Hero has 32A and Villain has 654, then, yes, either they are both drawing to the same suit or they each hold one of each other's outs. If Hero has 32A and Villain has 732, though, then they can each have their full complement of outs, for example: 3c 2s Ad (drawing to hearts: 456789TJK) 7d 3h 2c (drawing to spades: A45689TJQK) 
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#2
10-31-2007, 03:59 PM
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Re: Badugi Dilemma
Interesting. If they have at least one common card, and the opponent's common card is of the drawn-to suit, the blocker does not exist. Baysean analysis could tell me how often this happens, but I'm not sure I'll mess with it. [img]/images/graemlins/wink.gif[/img]
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