Two Plus Two Newer Archives  

Go Back   Two Plus Two Newer Archives > General Poker Discussion > Poker Theory
FAQ Community Calendar Today's Posts Search

 
 
Thread Tools Display Modes
Prev Previous Post   Next Post Next
  #1  
Old 05-23-2007, 08:17 AM
folding_the_nuts folding_the_nuts is offline
Junior Member
 
Join Date: May 2007
Posts: 18
Default math Problem in Tournament poker for advanced Players ( Sklansky)

Hi!! Can anybody help me?
Referring to DAVID SKLANSKY - TOURNAMENT POKER For Advanced Players


I've got some problems with one of David's calculations!
I don't know if I and my folks are just too stupid for this one or i miss something in the context because English isn't my native tongue.

My problem:

Chapter You're broke You're done:

two bets:
$200 to $100 on a coinflip
$120 to $100 on a coinflip

first bet is described in the book:
Expected value: 0,5 * (-100 $) + 0,5 * (200$) = 50

sounds pretty simple
According to this I apply this formula on the second bet:

Expected value : 0,5* (-100$) + 0,5* (-120$) = 10

he now claims that if he had the money and would make both bets he would have an EV of 35

That's my problem. At first glance I see that the average of my bets should be 30

Using the old formula:
I would win one time bet 1
I would win one time bet 2
I would lose 2 times ( 1+2)

0,5* (-100$) + (0,25 * 120$) + ( 0,25* 200$) = 30

that's my reasoning

David makes it so without detailed explanations:

0,5* (-100$) + 0,25*( 20$) +0,25 * (320$) which gives us an EV of 35

Can someone help me with this one. I'm pretty pissed off that I don't get this calculation

Formal and informative replies are appreciated

Folding_the _nuts
Reply With Quote
 


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 07:34 AM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.