#21
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Re: Beat I am mathematically challenged today
3 equations, 4 unknowns = infinite solution
the solution will be a curve so it's the portion of the graph where they are all >= 0. If that point is relative max then that is a solution. Is it? Is that right, what I said? I know you can't just use matrices and assume the solution is correct. |
#22
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Re: Beat I am mathematically challenged today *DELETED*
Had to edit..used the wrong equation
For all 3 equations on top, For 2 equations on bottom Stars SN: U6C84 |
#23
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Re: Beat I am mathematically challenged today
you're all wrong!
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#24
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Re: Beat I am mathematically challenged today
it turns out that one of the conditions is that they must be greater than zero. i should have said that earlier. if people are sick of this (i know i am), i can send the $$ to whoever answered it first. just pm me.
mods: please change my title to "Negative IQ". thanks. |
#25
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Re: Beat I am mathematically challenged today
Here it is with all Variables > 0
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#26
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Re: Beat I am mathematically challenged today
what kind of class maeks you do this tedious work with all these unreasonable conditions.
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#27
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Re: Beat I am mathematically challenged today
danzasmack is right. Four unknowns + three linear questions = infinitely many solutions.
Also, don't waste brains and ink and Excel on this, kids. There are websites for stuff like this. Pick anything you want for z, and the values of w, x, and y are: w = -(2*z-1)/2 x = 2*z y = -(4*z-1)/2 z = z Since you said they all have to be greater than zero, pick any z so that 0 < z < .25 |
#28
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Re: Beat I am mathematically challenged today
(1/4)<w<(1/2)
0<x<(1/2) 0<y<(1/2) 0<z<(1/4) |
#29
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Re: Beat I am mathematically challenged today
[ QUOTE ]
the solution will be a curve so it's the portion of the graph where they are all >= 0. [/ QUOTE ] LOL fourdimensionalcurveaments |
#30
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Re: Beat I am mathematically challenged today
[ QUOTE ]
(1/4)<w<(1/2) 0<x<(1/2) 0<y<(1/2) 0<z<(1/4) [/ QUOTE ] The working out: 6w + 6x + 4y + 2z = 5 ............ <font color="red"> Eq 1 </font> w + x + y + z = 1 ................. <font color="red"> Eq 2 </font> 12w + 8x + 8y + 12z = 10 ...... <font color="red"> Eq 3 </font> <font color="red"> Eq 1 </font> - 6( <font color="red"> Eq 2 </font>) -> y = (1 - 4z)/2 ............... <font color="blue"> Eq 4 </font> <font color="red"> Eq 3 </font> - 2(<font color="red"> Eq 1 </font>) -> x = 2z ......................... <font color="blue"> Eq 5 </font> <font color="red"> Eq 3 </font> - 8(<font color="red"> Eq 2 </font>) -> w = (1 - 2z)/2 ............... <font color="blue"> Eq 6 </font> From <font color="blue"> Eq 4 </font>: y > 0 y = (1 - 4z)/2 (1 - 4z)/2 > 0 z < (1/4).................... <font color="green"> Soln 1 </font> From <font color="blue"> Eq 5 </font>: x = 2z z < (1/4) x < (1/2)............ <font color="green"> Soln 2 </font> From <font color="blue"> Eq 4 </font> y = (1 - 4z)/2 z > 0 y < (1 - 4[0])/2 y < (1/2) ....................... <font color="green"> Soln 3 </font> From <font color="blue"> Eq 6 </font>: w = (1 - 2z)/2 z < (1/4) w > (1 - 2[1/4])/2 w > (1/4) z > 0 w < (1 - 2[0])/2 w < (1/2) (1/4) < w < (1/2) ........... <font color="green"> Soln 4 </font> |
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