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  #1  
Old 03-10-2007, 12:26 PM
Red_Diamond Red_Diamond is offline
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Default Same rank same color

Just a quick check to make sure I didn't skip the obvious.

Odds of two aces in the hole being dealt AND being the same color should be a 662-to-1 dog correct?
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  #2  
Old 03-10-2007, 04:53 PM
jay_shark jay_shark is offline
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Default Re: Same rank same color

2/1326 is equivalent to 1324:2 which is 662:1 .
Correct .
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  #3  
Old 03-10-2007, 11:59 PM
Red_Diamond Red_Diamond is offline
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Default Re: Same rank same color

There seems to be a missing digit (even after correcting from fraction to odds) for 2/1326 --> 1324:2

How did you arrive to that number?
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Old 03-11-2007, 12:11 AM
jay_shark jay_shark is offline
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Default Re: Same rank same color

This means that there are two red aces or two black aces .

1326 comes from 52c2=52*51/2=1326 . In other words , there are 1326 different hands . Two of the pairs are monotone aces .This means that 1324 pairs of hands are non- monotone aces . The odds against flopping monotone aces must be 1324:2 or equivalently dividing top and bottom by two we get 662:1 .

ie , the probability you roll a 1 from a 6 sided die is 1/6 . The odds against rolling a 1 are 5:1 . This means that five numbers are not 1's and one number is a 1 . Also , the odds in favor must be 1:5 which is just the exact opposite .

1/6 = odds against of (6-1):1

In general p/(p+q) is equivalent to odds against of (p+q-p) or q . Or odds in favor of p:q .
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  #5  
Old 03-11-2007, 11:36 AM
Red_Diamond Red_Diamond is offline
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Default Re: Same rank same color

Alright I see now.

I went about it by: (4/52)x(1/51)
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